Answer:
The z-score for this length is of 1.27.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
One-year-old flounder:
Mean of 127 with standard deviation of 22, which means that 
Anna caught a one-year-old flounder that was 155 millimeters in length. What is the z-score for this length
This is Z when X = 155. So
The z-score for this length is of 1.27.
f(x) + n - shift a graph of f n units up
f(x) - n - shift a graph of f n units down
f(x + n) - shift a graph of f n units left
f(x - n) - shift a graph of f n units right.
f(x) = x³, g(x) = (x - 2)³ - 3 = f(x - 2) - 3
2 units right and 3 units down.
To start, I had similar questions and I know that it takes 3 cones to fill a cylinder.
And as for the volumes:
V of a cylinder= V=π r<span>2 h (pi x radius squared x height)
Volume of a cone= V=</span><span>π r2 h/3 (pi x radius squared x height divided by 3)</span>
Answer:
<em>It has been given that Rectangle Q has an area of 2 square units.</em>
<em>Thea Drew a scaled version of Rectangle Q and marked it as R.</em>
<em>As you must keep in mind If we draw scaled copy of pre-image, then the two images i.e Pre-image and Image are similar.</em>
<em>As you have not written what is the scale factor of transformation</em>
<em>Suppose , Let the Scale factor of transformation= k</em>
<em>Rectangle Q = Pre -image, Rectangle R= Image</em>
<em>If, Pre-Image < Image , then scale factor is k >1.</em>
<em>But If, Pre-Image > Image , then Scale factor will be i.e lies between, 0<k<1.</em>
Both taxis will leave together at 04:18 PM after 04:00 PM
Step-by-step explanation:
We have to use the LCM to find the time on which both will leave at the same time,
Given
Departure interval for first taxi = 6 minutes
Departure interval for second taxi = 9 minutes
We have to find the LCM of 9 and 6
So,
Factors of 6: 6,12,<u>18</u>,24,30,36,42,48,54,60
Factors of 9: 9,<u>18</u>,27,36,45,54,63,72
The LCM is 18.
So,
Both taxis will leave together at 04:18 PM after 04:00 PM
Keywords: LCM, time
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