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natta225 [31]
3 years ago
15

A material that cannot be broken down farther by chemical means

Chemistry
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

<em>An element is the material  that cannot be broken down further by chemical means.</em>

Explanation:

An element can be described as a material which is made up of only one kind of atom. For example, argon, hydrogen etc. An element cannot be broken down further by physical or chemical means.

Compounds, on the other hand, are made of different kinds of atoms. They can be broken down to simpler molecules by chemical means. For example, water is a compound made up of hydrogen and oxygen.

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What is produced when calcium reacts with fluorine in a synthesis reaction?
Thepotemich [5.8K]
C is the correct answer (CaF2) (sorry dont have subscript)

Explanation: synthesis reaction forms a compound and calcium reacting with fluorine produces Calcium Fluoride (CaF2) chemical name
4 0
3 years ago
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Consider the balanced chemical equation for the combustion of methane (CH4).
Mrac [35]
<h3>Answer:</h3>

                  89.6 L of O₂

<h3>Solution:</h3>

The balanced chemical equation is as,

                                CH₄  +  2 O₂    →    CO₂  +  2 H₂O

As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

             44 g ( 1 mol) CO₂ is produced by  =  44.8 L (2 mol) of O₂

So,

                  88 g CO₂ will be produced by  = X L of O₂

Solving for X,

                        X = (88 g × 44.8 L) ÷ 44 g

                        X = 89.6 L of O₂

5 0
3 years ago
Read 2 more answers
What is the mass of an object that has a total heat loss of 550. cal, a specific heat of
Galina-37 [17]

Answer:

the mass is .587 J/g°C

Explanation:

................

4 0
2 years ago
23°C = ______ K<br><br> -250<br> 296<br> 123<br> 23
strojnjashka [21]

Answer:

296

Explanation:

6 0
3 years ago
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3. How much energy is needed to raise 45 grams of water from 40°C to 115 °C?
Dafna1 [17]

Answer:

Q = 114349.5 J

Explanation:

Hello there!

In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:

Q_1=45g*4.18\frac{J}{g\°C}*(100\°C-40\°C)=11286J\\\\Q_2=45g* 2260 \frac{J}{g} =101700J\\\\Q_3=45*2.02\frac{J}{g\°C}*(115\°C-100\°C)=1363.5J

Thus, the total energy turns out to be:

Q_T=11286J+101700J+1363.5J\\\\Q_T=114349.5J

Best regards!

5 0
3 years ago
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