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3 years ago

A student burns 1.50 mol C3H8 according to the following reaction:

Chemistry

2 answers:

daser333 [38]3 years ago

5 0

Answer:

198.45 g CO₂

Explanation:

Data:

The equation for combustion is given as follows:

C3H8 + 5O2 = 3CO2 + 4H2O

Number of moles of C₃H₈ burned = 1.50

Number of moles of CO₂ formed = 3 (1.50)

= 4.50 moles

mass of CO₂ = number of moles × Mr

= 4.50 × 44.10

= 198.45 grams

g100num [7]3 years ago

3 0

1.50 mol C3H8 X (3 mol CO2 / 1 mol C3H8) X (44.0 g CO2 / 1 mol CO2) = 198 g CO2

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Calculate the molecular weight of a substance. In which the solution of this substance in the water has a concentration of 7 per

Eduardwww [97]

Answer : The molecular weight of a substance is 157.3 g/mol

Explanation :

As we are given that 7 % by weight that means 7 grams of solute present in 100 grams of solution.

Mass of solute = 7 g

Mass of solution = 100 g

Mass of solvent = 100 - 7 = 93 g

Formula used :

$\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=k_f\times\frac{\text{Mass of substance(solute)}\times 1000}{\text{Molar mass of substance(solute)}\times \text{Mass of water(solvent)}}$

where,

$\Delta T_f$ = change in freezing point

$T_f^o$ = temperature of pure water = $0^oC$

$T_f$ = temperature of solution = $-0.89^oC$

$K_f$ = freezing point constant of water = $1.86^oC/m$

m = molality

Now put all the given values in this formula, we get

$(0-(-0.89))^oC=1.86^oC/m\times \frac{7g\times 1000}{\text{Molar mass of substance(solute)}\times 93g}$

$\text{Molar mass of substance(solute)}=157.3g/mol$

Therefore, the molecular weight of a substance is 157.3 g/mol

7 0

3 years ago

6. 5.50 x 10- molecules of carbon dioxide to moles.

sergeinik [125]

1.24973017189471 is probably the answer to your equation

4 0

3 years ago

The reason an increase in substrate concentration does not increase the reaction rate indefinitely is because

scoundrel [369]

Answer:

Increasing substrate concentration also increases the rate of reaction to a certain point. Once all of the enzymes have bound, any substrate increase will have no effect on the rate of reaction, as the available enzymes will be saturated and working at their maximum rate.

3 0

3 years ago

PLEASE HELPPPP! HOW DO I DO THIS???

kow [346]

Answer:

1552.83J Released

Explanation:

1. mass/m=225

Initial temp:86C, final:32.5C

Changed Temp: 32.5-86= -53.5C

s=0.129 J/gC

Formula: q= m times s times changed Temp.

q=(225)(0.129)(-53.5)

q= -1552.83 J

q=1552.83 J Released

8 0

3 years ago

A 40 g sample of water absorbs 500 calories of energy, how much did the water temp changed?

Dafna1 [17]

2.99 °C is the change in temperature if a 40 g sample of water absorbs 500 calories of energy.

<h3>What is specific heat capacity?</h3>

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given data:

m = 40 g

Q = 500 J

Specific heat capacity of water = 4.18 J/g°C

Change in Temperature =?

The formula for Heat Energy is given by:

Q = mcp∆T

where: Q - Heat Energy

m - mass

cp - specific heat

∆T = change in temperature, $T_2 - T_1$

Solution:

Substituting the value of m, specific heat capacity of water and Q in the formula,

500 J = (40 g)(4.18 J/g°C)(∆T)

∆T = 2.99 °C

Learn more about the specific heat capacity here:

https://brainly.ph/question/7099790

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4 0

2 years ago