Question

A student burns 1.50 mol C3H8 according to the following reaction:

Answer 1

Answer:

198.45 g CO₂

Explanation:

Data:

The equation for combustion is given as follows:

C3H8 + 5O2 =  3CO2 + 4H2O

Number of moles of C₃H₈ burned = 1.50

Number of moles of CO₂ formed = 3 (1.50)

                                                       = 4.50 moles

mass of CO₂  = number of moles  × Mr

                      = 4.50 × 44.10

                      = 198.45 grams

Answer 2

1.50 mol C3H8 X (3 mol CO2 / 1 mol C3H8) X (44.0 g CO2 / 1 mol CO2) = 198 g CO2