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3 years ago

What types of electromagnetic radiation does the sun emit?

Physics

1 answer:

Ksju [112]3 years ago

5 0

Answer:

https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf

Explanation:

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Do you think most other people participate in these measures?

Fynjy0 [20]

what?theres no picture. what does this mean?

3 0

4 years ago

Metals are good conductors of electricity because __________ . A) they are easily reduced and oxidised. B) they are easily ionis

Advocard [28]

Answer:

Explanation:

because they are easily reduced and oxidised

3 0

3 years ago

Assuming that the smallest measurable wavelength in an experiment is 0.950 fm , what is the maximum mass of an object traveling

Arada [10]

Answer:

The maximum mass is $2.89x10^{-21}Kg$

Explanation:

The wavelength of the electron can be determined by means of the De Broglie equation.

$\lambda = \frac{h}{p}$ (1)

Where h is the Planck's constant and p is the momentum.

$\lambda = \frac{h}{mv}$

$m = \frac{h}{\lambda v}$ (2)

Where m is the mass and v is the velocity.

Before using equation 2 it is necessary to express the wavelength from femtometers to meters.

$\lambda = 0.950fm .\frac{1m}{1x10^{15}fm}$ -- $9.5x10^{-16}m$

Finally, equation 2 can be used.

$m = \frac{6.624x10^{-34} J.s}{(9.5x10^{-16}m)(241m/s)}$

But $1J = Kg.m^{2}/s^{2}$

$m = \frac{6.624x10^{-34} Kg.m^{2}/s^{2}.s}{(9.5x10^{-16}m)(241m/s)}$

$m = 2.89x10^{-21}Kg$

Hence, the maximum mass is $2.89x10^{-21}Kg$

6 0

3 years ago

Read 2 more answers

As you travel from Detroit in a certain direction, the outside temperature, T (in degrees), depends on your distance, d (in mile

Ber [7]

Answer:

a) $\Delta T= 100^{\circ}C$

b) $\bigtriangledown T=1^{\circ}C.mile^{-1}$

c) $\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

d) $\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

Explanation:

Given is the data of variation of temperature with respect to the distance traveled:

Temperature T as a function of distance d:

$T=(d+30) ^{\circ}C$ ...................................(1)

(a)

Total change in temperature from the start till the end of the journey:

$\Delta T= T_f-T_i$ ..............................(2)

where:

$T_f$ = final temperature

$T_i$ = initial temperature

∵In the start of the journey d = 0 miles & at the end of the journey d = 100 miles.

So, correspondingly we have the eq. (2) & (1) as:

$\Delta T= (100+30)-(0+30)$

$\Delta T= 100^{\circ}C$

(b)

Now, the average rate of change of the temperature, with respect to distance, from the beginning of the trip to the end of the trip be calculated as:

$\bigtriangledown T=\frac{\Delta T}{\Delta d}$ ......................(3)

where:

$\Delta d$ = change in distance

$\bigtriangledown T=$ change in temperature with respect to distance

putting the respective values in eq. (3)

$\bigtriangledown T=\frac{100}{100}$

$\bigtriangledown T=1^{\circ}C.mile^{-1}$

(c)

comparing the given function of the temperature with the general equation of a straight line:

$y=m.x+c$

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

$\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

(d)

comparing the given function of the temperature with the general equation of a straight line:

$y=m.x+c$

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

$\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

4 0

4 years ago

As the mass of an object increases, the weight of the object will ______?

Sergio039 [100]

Answer:

also increase

Explanation:

If the mass increases so will the weight.

4 0

3 years ago