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zhenek [66]
3 years ago
13

Match the block to its correct density. 1. Block A 0.64 Kg/L 2. Block B 0.917 kg/L 3. Block C 0.70 Kg/L 19.3 kg/L 4. Block D 3.5

3 Kg/L 5. Block E​
Physics
1 answer:
Sedbober [7]3 years ago
4 0

Answer:

quit school aghahahha

Explanation:

xD

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An air-filled parallel-plate capacitor is constructed with a plate area of 0.40 m2 and a plate separation of 0.10 mm. It is then
seropon [69]

Answer:

The charge stored  is  Q =  4.25 *10^{-7 } \ C

The energy stored is  E = 2.55*10^{-6} \ J

Explanation:

From the question we are told that

    The area of the plates is  A =  0.40 \ m^2

     The separation between the plate is d =  0.10 \ mm =0.0001 \ m

      The potential difference is  V =  12 \ V

       The permitivity of free space is  \epsilon_o  = 8.85 *10^{-12} C^2 \cdot N^{-1} \cdot m^2

         The dielectric constant of glass is K =  5.0

Generally the capacitance of this capacitor is

      C =  \frac{\epsilon_o  * A}{d}

substituting values

       C =  \frac{8.85*10^{-12}  * 0.40}{0.0001}

        C =   3.34 *10^{-8} \ C

The charge stored is mathematically evaluated as

         Q = CV

substituting values

        Q =  (3.54*10^{-8} * 12)

         Q =  4.25 *10^{-7 } \ C

The energy stored is  

         E =  0.5 *  CV^2

substituting values

         E =  0.5 *  (4.25 *10^{-7} * 12^2)

           E = 2.55*10^{-6} \ J

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3 years ago
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At point C because it is at the lowest position.

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