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Ymorist [56]
3 years ago
14

How does gravity make a star

Physics
1 answer:
gavmur [86]3 years ago
5 0
Gravity pulls large masses of debris together, forming a star<span />
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Which is a true statement regarding the law of mass balance? A.Solids, gases, and liquids have their own specific equations for
nata0808 [166]

Answer:

b. when the body converts a nutrient  to another substance, there  is no effect on mass balance.

Explanation:

The law of mass balance states that the mass stays the same in any chemical reaction, that is the reason why a nutrient in human body transforms to another substance like another substance, into muscles (that has mass), a body fluid ( that has mass) or another substance, but the total mass will keep the same, just in a different shape, nature or state.

6 0
4 years ago
Convert 1 mm to meters using scientific notation. Include units in your answer.
miskamm [114]

Answer:

1.0 x 10^-3 m

Explanation:

1mm = (1/1000) m = 0.001m = 1.0 x 10^-3m (because to get 1.0, you have to  movi the decimal point in the "0.001" three spots over to the right)

3 0
3 years ago
A -5.0 μC charge experiences a 11 i^ N electric force in a certain electric field. [Recall that i^ is a unit vector in the x-dir
Pachacha [2.7K]

Answer:

\vec{F}= -3.52\times 10^{-13}\hat{i}\ N

Explanation:

given,

charge = -5.0 μC

Electric force, F = 11 i^ N

force would a proton experience = ?

we know

\vec{F} = q \vec{E}

11\hat{i} = -5 \times 10^{-6} \vec{E}

\vec{E} =-2.2 \times 10^{6}\hat{i}

we know charge of proton is equal to 1.6 x 10⁻¹⁹ C

using formula

\vec{F} = q \vec{E}

\vec{F}= 1.6 \times 10^{-19}\times -2.2 \times 10^{6}\hat{i}

\vec{F}= -3.52\times 10^{-13}\hat{i}\ N

Force experienced by the photon in the same field is equal to \vec{F}= -3.52\times 10^{-13}\hat{i}\ N

3 0
3 years ago
Why doesn't the skateboarder rolls as high up the ramp each time you go down the ramp ​
Alexandra [31]
Because of the law of inertia and it’s effect on the skater
5 0
3 years ago
The girl makes a microscope with a 3.0 cm focal length objective and a 5.0 cm eyepiece. The microscope tube length is 10 cm. Use
saul85 [17]

To solve this problem we will use the concepts related to Magnification. Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification".

The overall magnification of microscope is

M = \frac{Nl}{f_ef_0}

Where

N = Near point

l = distance between the object lens and eye lens

f_0= Focal length

f_e= Focal of eyepiece

Given that the minimum distance at which the eye is able to focus is about 25cm we have that N = 25cm

Replacing,

M = \frac{25*10}{3*5}

M = 16.67\approx 17\\

Therefore the correct answer is C.

3 0
4 years ago
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