The statements of both students are incorrect.
-- Electrical power, just like mechanical power, is expressed in units of watts.
-- 'Coulomb' is the unit of electrical charge.
-- '400 k ohms' means 400,000 ohms of resistance.
-- 'Volt' is the unit of electromotive force (or potential difference).
There are no 'following statements'.
All in all, a very disappointing question.
The capacitive reactance is reduced by a factor of 2.
<h3>Calculation:</h3>
We know the capacitive reactance is given as,
where,
= capacitive reactance
f = frequency
C = capacitance
It is given that frequency is doubled, i.e.,
f' = 2f
To find,
=?
Therefore, the capacitive reactance is reduced by a factor of 2.
I understand the question you are looking for is this:
A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?
- The capacitive reactance is doubled.
- The capacitive reactance is traduced by a factor of 4.
- The capacitive reactance remains constant.
- The capacitive reactance is quadrupled.
- The capacitive reactance is reduced by a factor of 2.
Learn more about capacitive reactance here:
brainly.com/question/23427243
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It looks like the diagram is telling you that there is a net force of 8 N + 4 N = 12 N pointed to the right. By Newton's second law, the magnitude of the net force <em>F</em> is equal to the mass <em>m</em> times the acceleration <em>a</em> :
<em>F</em> = <em>m</em> <em>a</em>
12 N = (4 kg) <em>a</em>
<em>a</em> = (12 N) / (4 kg)
<em>a</em> = 3 m/s²
Answer:it's not
Explanation:there's no proof.
Answer:
If you meant 2.34, 2.34 meters = 23.4 decimeters.
Formula: multiply the value in meters by the conversion factor '10'.
So, 2.34 meters = 2.34 × 10 = 23.4 decimeters.
Hope that helps. x