Answer:
The answer to your question is below
Explanation:
Data
Volume 1 = V1 = 3000 l
Temperature 1 = T1 = 30°C
Pressure 1 = P1 = 99 kPa
Volume 2 = ?
Temperature 2 = T2 = 16°C
Pressure 2 = P2 = 45.5 kPa
Process
1.- To find the new volume we need to convert the temperature to °K
T1 = 30 + 273 = 303°K
T2 = 16 + 273 = 289°K
2.- Use the Combined gas law
P1V1/T1 = P2V2/T2
-Solve it for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (99 x 3000 x 289) / (303 x 45.5)
-Result
V2 = 85833000 / 13786.5
V2 = 6225.8 l
There are no conversion factor ratios.
Lignite
This is the softest, youngest, and wettest rank of coal, often referred to as "brown coal" with a carbon content of only 25-35% and correspondingly lower energy content.
A. The molecules of solids are close together and compact, liquids are spread out but not too far apart, and gas molecules are really far apart.
B. Increase in temperature causes pressure to go up. Decrease in temperature cause pressure to go down
Number of moles = mass / molar mass
number of moles of H2 = (<span>6.96×10−4) / (2)(1) = 3.48*10^-4 moles
</span>The equation that describes the formulation of NH3 is:
N2 + 3H2 .......> 2NH3
From the balanced chemical equation, we can see that:
3 moles of H2 produces 2 moles of NH3
Based on this, to know the number of moles of NH3 produced from 3.48*10^-4 moles of hydrogen, we will do cross multiplication as follows:
number of moles = (3.48*10^-4*2) / (3) = 2.32*10^-4 moles
Now, one mole of any element contains Avogadro's number of molecules. Therefore, number of molecules in 2.32*10^-4 moles can be calculated as follows:
number of molecules = 2.32 * 10^-4 * 6.022 * 10^23 = 1.397 * 10^20 molecules
Answer:
8613.5 g
Explanation:
The formula for the calculation of moles is shown below:
For
Mass of = 300 g
Molar mass of = 2.016 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the given reaction:
4 moles of will react 1 mole of
1 mole of will react 1/4 mole of
148.81 moles of will react 148.81/4 mole of
<u>Moles of required = 37.2025 mol</u>
Molar mass of = 231.53 g/mol
<u>Mass of = Moles × Molar mass = 37.2025 × 231.53 g = 8613.5 g
</u>