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shepuryov [24]
2 years ago
13

Calculate the vapor pressure of a solution of 32.5 g of glycerol (C3H8O3) in 500.0 g of water at 25°C. The vapor pressure of wat

er at 25°C is 23.76 torr. (Assume ideal behavior.)
Chemistry
1 answer:
Luba_88 [7]2 years ago
5 0

The vapor pressure is obtained as 23.47 torr.

<h3>What is the vapor pressure?</h3>

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp =  vapor pressure lowering

x2 = mole fraction of the  of the solute

Number of moles of  glycerol =  32.5 g/92 g/mol = 0.35 moles

Number of moles  of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp =  0.012 * 23.76 torr

Δp =  0.285 torr

p1 = p° - Δp

p1 = 23.76 torr -  0.285 torr

p1 = 23.47 torr

Learn more about vapor pressure:brainly.com/question/14718830

#SPJ1

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lawyer [7]

<em>Answer:</em>

  • At 60 centigrade, the kinetic energy of the substance will be greatest.

<em>Explanation:</em>

As we know, the kinetic energy of substance is directly proportional to Temperature.

The total Kinetic energy can be calculated as follow

                                                K.E = 3/2 n.R.T

From the equations, it is cleared that Temperature is directly proportional to temperature.

7 0
3 years ago
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jok3333 [9.3K]

Answer:

1 mole represents 6.023×1023 particles.

1 mole of iodine atom= 6.023×1023

Given 127.0g of iodine.

no. of iodine atom = 1 mole of iodine

1mole of magnesium = 24g of Mg = 6.023×1023no.of Mg

Given 48g of Mg = 2×6.023×1023

no. of Mg = 2 moles of Mg

1 mole of chlorine atom= 6.023× 1023

no. of chlorine atom = 35.5g of chlorine atom

Given 71g of chlorine atom=2× 6.023× 1023

no. of chlorine atom = 6.023×1023

2 moles of chlorine atom.

Given that 4g of hydrogen atom.

will be equal to 4 × 6.023 × 1023

no. of atoms of hydrogen= 4 moles of hydrogen atom.

7 0
3 years ago
Predict the boiling point of water at a pressure of 1.5 atm.
Lina20 [59]

Answer:

100.8 °C

Explanation:

The Clausius-clapeyron equation is:

ln\frac{P_{1} }{P_{2}} =-Δ\frac{H_{vap}}{r} (\frac{1}{T_{2}}-\frac{1}{T_{1}}  )

Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'

Isolating for T2 gives:

T_{2}=(\frac{1}{T_{1}} -\frac{Rln\frac{P_{2}}{P_{1}} }{Delta H_{vap}}

(sorry for 'deltaHvap' I can not input symbols into equations)

thus T2=100.8 °C

7 0
2 years ago
A solution is prepared by dissolving 0.23 mol of chloroacetic acid and 0.27 mol of sodium chloroacetate in water sufficient to y
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Answer:

c. chloroacetate ion

Explanation:

The chloroacetic acid, ClCH₂CO₂H, is a weak acid with Ka = 1.36x10⁻³. When this weak acid is in solution with its conjugate base, ClCH₂CO₂⁻ (From sodium chloroacetate) a buffer is produced. The addition of a strong acid as the HCl produce the following reaction

HCl + ClCH₂CO₂⁻ → ClCH₂CO₂H + Cl⁻.

Where the acid reacts with the chloroacetate ion to produce more chloroacetic acid

That means, the HCl reacts with the chloroacetate ion present in the buffer solution

Right answer is:

<h3>c. chloroacetate ion</h3>
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Good job! Could get a 100

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