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3 years ago

Ng an algebraic procedure, as shown below.

Mathematics

1 answer:

Anastaziya [24]3 years ago

5 0

Answer:

can you make it more clear

Step-by-step explanation:

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Find \tan(\beta)tan(β)tangent, left parenthesis, beta, right parenthesis in the triangle.

goldenfox [79]

Answer:

the correct answer is C 8/15

Step-by-step explanation:

3 0

3 years ago

The area on a wall covered by a rectangular poster is 270 square inches. The length of the poster is 1.2 times longer than the w

forsale [732]

Answer:

Length = 18 in

Width = 15 in

Step-by-step explanation:

We have that the area of a rectangle is:

A = L * W

but L = 1.2 * W

A = 1.2 * (W ^ 2)

1.2 * (W ^ 2) = 270

(W ^ 2) = 270 / 1.2

W ^ 2 = 225

Therefore, W is equal to:

W = 225 ^ (1/2)

W = +/- 15, but only +15 makes sense

W = 15

Now for L:

L = 1.2 * 15

L = 18

A = 15 * 18 = 270 in ^ 2

4 0

3 years ago

During the day,Sam spent $4.85 on lunch.he also bought 2 books for $7.95 each. At the end of the day we had $8.20 left how much

Vlada [557]

20.75 because if you add 4.85+7.95+7.95 add that you get 20.75

7 0

3 years ago

Reflect C over the y axis

4vir4ik [10]

Answer:

C' (- 3, 2 )

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

C (3, 2 ) → C' (- 3, 2 )

4 0

3 years ago

PLEASE HELP ASAP !!

wariber [46]

Answer:

First figure: $954cm^3$

Second figure: $1,508yd^3$

Third figure:

Height= q
Side length = r

Fourth figure:  $726cm^3$

Explanation:

A. First figure:

1. Formula:

$\text{Volume of a cylinder}=\pi \times radius^2\times length$

2. Data:

radius = 9cm / 2 = 4.5cm

length = 15 cm

3. Substitute in the formula and compute:

$Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3$

B. Second figure

1. Formula:

$\text{Volume of a leaned cylinder}=\pi \times radius^2\times height$

2. Data:

radius = 12yd

height = 40 yd

3. Substitute and compute:

$Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3$

C) Third figure

a) The height is the segment that goes vertically upward from the center of the base to the apex of the pyramid, i.e. q .

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e. r .

When the base of the pyramid is a square the four edges of the base have the same side length.

D) Fourth figure

1. Formula

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

$Volume=(1/3)B\times H$

2. Data:

height: H = 18cm

side length of the base: 11 cm

3. Calculations

a) Calculate the area of the base.

The base is a square of side length equal to 11 cm:

$\text{Area of the base}=B=(11cm)^2=121cm^2$

b) Volume of the pyramid:

$Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3$

4 0

3 years ago

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