A person would be driving 4 blocks west from the starting point to make the shorter distance while maintaining same displacement.
<u>Explanation:</u>
The measurement of an object’s position change from its point is called displacement. It is usually calculated from starting to the end points and represented by ‘delta s’. In the given scenarios, the person drove in the way that he finals the driving by 4 blocks away from the west.
Means, the persons drive to 8 blocks north and then to 8 blocks south get cancelled. Hence, to make the shorter distance with maintaining same displacement he would be driving 4 blocks west from the starting point.
Given that,
Puck slide total Deltax = 12m
Puck and board Mk = 0.10
Find the initial speed = ?
We know that,
Vf^2-Vi^2 = 2a Deltax
-Vi^2 = -2MkgDeltax ............(1)
then,
fk = -Mk mg = ma
a = -Mkg .........(2)
From equation (1),
Vi^2 = 2MkgDeltax
Vi = âš2MkgDeltax [g=9.8m/s^2]
Vi = âš2(0.10)(0.98)(12)
Vi = âš0.2(9.8)(12)
Vi = âš1.92(12)
Vi = âš23.52
Vi = 4.8 m/s
Therefore the initial speed of the puck Vi = 4.8 m/s
Answer:
A title
Explanation:
Because this is middle school.
