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vfiekz [6]
3 years ago
11

What is the kinetic energy of a 1,350kg car traveling at a speed of 12m/s?

Physics
1 answer:
Ainat [17]3 years ago
7 0
Kinetic energy= 1/2 m v^2

so... 1/2(1350)(12^2)

kinetic energy = 97200Joules
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3 years ago
Fermi energy of conduction electrons in silver is 0.548 J. Calculate the number of such electrons in unit cm3
ICE Princess25 [194]

Answer:

n=1.86*10^{-30}m^3

Explanation:

From the question we are told that:

Fermi energy of conduction electrons E_f=0.548J

Generally the equation for Fermi energy is mathematically given by

 E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}

 E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}

 {n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}

Where

h= Planck's constant

 {n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}

 {n^{2/3}}=\frac{0.548J}{3.62*10^{-19}}

 n=(1.51*10^{-20})^{3/2}

 n=1.86*10^{-30}m^3

3 0
3 years ago
The formula d = 1.1 t 2 + t + 1 expresses a car's distance (in feet to the north of an intersection, d , in terms of the number
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d(t) = 1.1t² + t + 1

The constant speed required to cover the same distance between t = 3 to t = 5 is the same as the average speed over that same time interval. It is given by:

v = Δx/Δt

v = average speed, Δx = change in distance, Δt = elapsed time

Given values:

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Plug in and solve for v:

v = 19.6/2

v = 9.8ft/s

5 0
4 years ago
Read 2 more answers
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