Answer:
omg i'm so sorry, i hope you get better <3!
Explanation:
Answer:
The magnitude of the horizontal net force is 13244 N.
Explanation:
Given that,
Mass of car = 1400 kg
Speed = 17.7 m/s
Distance = 33.1 m
We need to calculate the acceleration
Using equation of motion

Where, u = initial velocity
v = final velocity
s = distance
Put the value in the equation



Negative sign shows the deceleration.
We need to calculate the net force
Using newton's formula



Negative sign shows the force is opposite the direction of the motion.
The magnitude of the force is

Hence, The magnitude of the horizontal net force is 13244 N.
Answer:
The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.