When a polypeptide is in its native conformation,there are weak interactions between its R groups. However, when it is denatured
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Answer:
Concentration of original solution = 1.66
Explanation:
We know that
We have given concentration of NaOH = 0.1678
Volume of NaOH = 19.88 mL = 0.01988 L
So moles of NaOH = volume x concentration of NaOH
=
Moles of in 10 mL of diluted solution = 1/2 x moles of NaOH
= x 0.00333 = 0.00166 mol
Moles of in 25 mL of original solution
= moles of H2SO4 in 250 mL of diluted solution
= x 0.00166 = 0.0415 mol
Concentration of original solution =
=