All categories

1 year ago

Answer Questions 7-11 based on Figure 2.

Chemistry

1 answer:

bixtya [17]1 year ago

7 0

Answer:

6. 10 protons

10 electrons

neutral

7. 10 protons

8. Neon

9. 10 electrons

11. No

12. it's not an ion

Explanation:

count the number of electron in the shells, the number of electrons is equal to the number of protons, which is equal to the atomic number

You might be interested in

What method of heat transfer occurs when your skin feels hot outside on a sunny, summer day?

Stolb23 [73]

Answer:

i checked it again it's B

Explanation:

radiation sorry

4 0

2 years ago

Read 2 more answers

Estructura 7.2 completar repaso 1 - ¿lógico o ilógico? 1 - ¿lógico o ilógico? listen and indicate whether each question and resp

Vsevolod [243]

say it in English please.

8 0

2 years ago

Which of the following is physical change!?

Lemur [1.5K]

<h2>_______________________</h2><h2 /><h2 /><h2>D - All of The Above</h2>

<h3>Dissolve:</h3>

To Become or cause to become incorporated into a liquid so as to form a solution.

<h3>Evaporation:</h3>

The process of changing from liquid to vapour.

<h3>Bending:</h3>

To shape or force something straight, in a curve or angle.

___________________________________

6 0

2 years ago

Zinc metal reacts with hydrochloric acid to produce zinc(II) chloride and hydrogen gas. How many liters of hydrogen gas will be

AleksAgata [21]

Answer:

0.120 L of hydrogen gas will be produced

Explanation:

Step 1: Data given

Mass of zinc = 10.0 grams

Volume of hydrochloric acid = 23.8 mL

Molarity of hydrochloric acid = 0.45 M

Molar mass of zinc =65.38 g/mol

Step 2: The balanced equation

Zn + 2HCl → ZnCl2 + H2

Step 3: Calculate moles Zinc

Moles Zn = mass Zn / molar mass Zn

Moles Zn = 10.0 grams / 65.38 g/mol

Moles Zn = 0.153 moles

Step 4: Calculate moles HCl

Moles HCl = molarity * volume

Moles HCl = 0.45 M * 0.0238 L

Moles HCl = 0.01071 moles

Step 5: Calculate limiting reactant

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

HCl is the limiting reactant. It will completely be consumed (0.01071 moles)

Zn is in excess. There will react 0.01071/2 = 0.005355 moles

There will remain 0.153 - 0.005355 = 0.147645 moles

Step 6: Calculate moles H2

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

For 0.01071 moles HCl we'll have 0.005355 moles H2

Step 7: Calculate volume H2

1 mol at STP = 22.4 L

0.005355 moles = 22.4 * 0.005355 = 0.120 L = 120 mL

0.120 L of hydrogen gas will be produced

4 0

3 years ago

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

4 0

2 years ago