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2 years ago

If a motorcyclist accelerates from rest to 40 m/s in 8 seconds, what is their acceleration?

Chemistry

1 answer:

Ray Of Light [21]2 years ago

8 0

It’s A it’s division not multiplication

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A gas at a constant volume has an initial temperature of 300.0 K and an initial pressure of 10.0 atm. What pressure does the gas

harkovskaia [24]

$\frac{500}{300} times 10=16.667 atm$

4 0

3 years ago

Which of the following is the smallest volume? (2 points) 2500 mL

Virty [35]

So to put them all in the same units we have
2500 mL 
250 mL 
25mL 
2,500,000,000mL 

So the third one is the smallest

6 0

3 years ago

Read 2 more answers

Last question help im confusion

Andrej [43]

Remark

The given thing on the right is a positron. The mass for these subatomic particles is considered to be 0. It's atomic number is 1 which means it is a blood relative of a proton.

So essentially what happens is that X is one space to the left on the periodic table. But let's solve this a little bit more formally.

Solution

$_{65}^{147}\text{Tb}\longrightarrow _{z}^{y}\text{x} +_{1}^{0}{e}$

y stays the same at 147. It is z that changes.

65 = z + 1 Subtract 1 from both sides.

64 = z

So the chemical with 64 as its position on the periodic table is

Gadolinium and the answer is C

5 0

3 years ago

(BRAINLIEST) Coal burning plants produce less air pollution than nuclear power plants

Alecsey [184]

Answer:

the answer of this question is true

7 0

3 years ago

Identify the Bronsted-Lowry acid, the Bronsted-Lowry base, the conjugate acid and the conjugate base for each of the following r

Vlad1618 [11]

Answer:

Acids → H₂CO₃ from equilibrium 1 and water, from equilibrium 2.

Bases → Water from equilibrium 1 and ammonia from equilibrium 2.

In 1st equilibrium, H₃O⁺ is the conjugate acid and HCO₃⁻ the conjugate base.

In 2nd equilibrium, NH₄⁺ is the conjugate acid, and OH⁻, the conjugate base.

Explanation:

By the Bronsted-Lowry you know that acids are the one that release protons and base are the ones that catch them.

For the first equilibrium:

H₂CO₃(aq) + H₂O(l) ⇄ H₃O⁺(aq) + HCO₃⁻(aq)

Carbonic acid is the acid → It donates the proton to water, so the water becomes the base. As H₂CO₃ is the acid, the bicarbonate is the conjugate base (it can accept the proton from water to become carbonic acid, again) and the hydronium is the conjugate acid (it would release the proton to become water).

For the second equilibrium:

NH₃(aq) + H₂O(l) ⇄ NH₄⁺ (aq) + OH⁻(aq)

This is the opposite situation → Water relase the proton to ammonia, that's why water is the acid and NH₃, the base (it accepted to become ammonium). The NH₄⁺ is the conjugate acid (it can release the H⁺ to become ammonia) and the OH⁻ is the conjugate base (It can accept the proton to become water, again).

5 0

3 years ago