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4 years ago

Which is most likely the length of a student’s textbook?

Physics

2 answers:

UkoKoshka [18]4 years ago

3 0

For this case, what we must do is to rewrite these measurements in the same unit in order to compare them.

By writing the measurements in meters we have:

$30 mm = (30) * (\frac{1}{1000}) = 0.030 m$

$30 cm = (30) * (\frac{1}{100}) = 0.30 m$

$30 dm = (30) * (\frac{1}{10}) = 3 m\\30 Hm = (30) * (100) = 3000 m$

Therefore, physically the correct measure is:

$0.30 m = 30 cm$

Answer:

the length of a student's textbook most likely is:

30 centimeters

LenKa [72]4 years ago

3 0

Answer:

30 centimeters

Explanation:

I just took the quiz and I got a 100 on it

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What is the force required to lift the balloon with

Olin [163]

No force is required to lift that balloon. In fact, force is required to hold it down, and if you let go, it's up, up, and away.

Since the balloon's density is less than the density of the air around it, it's lighter than the air it displaces, there is a net upward buoyant force acting on it, and it floats up !

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4 years ago

A child in danger of drowning in a river is being carried down-stream by a current that flows uniformly with a speed of 2.20 m/s

zmey [24]

Answer:

The angle is 65.6°.

Explanation:

Given that,

Speed = 2.20 m/s

Distance from the shore= 500 m

Distance from the bottom= 1100 m

Speed of boat = 7.30 m/s

According to figure,

We need to calculate the angle with shore

Using formula of angle

$\tan\theta=\dfrac{y}{x}$

Put the value into the formula

$\tan\theta=\dfrac{500}{1100}$

$\theta=\tan^{-1}(\dfrac{500}{1100})$

$\theta=24.4^{\circ}$

We need to calculate the angle

$\alpha=90-\theta$

Put the value into the formula

$\alpha=90-24.4$

$\alpha=65.6^{\circ}$

Hence, The angle is 65.6°.

5 0

3 years ago

A 1,550 kg car moving south at 10.0 m/s collides with a 2,550 kg car moving north. The cars stick together and move as a unit af

nikitadnepr [17]

Answer:

14.47 m/s

Explanation:

The momentum must be preserved before and after the collision:

The total momentum before the collision

$m_1v_1 + m_2v_2$

where $m_1 = 1550 kg, m_2 = 2550 kg$ are the masses of the car moving south and north, respectively, before the collision. $v_1 = -10m/s$ is the velocity of the car moving South. We take the velocity to the North as the positive direction

The total momentum after the collision

$(m_1 + m_2)V$

where V = 5.22m/s is the velocity of both cars after the collision

We can equalize the 2 equations and plug in the numbers:

$m_1v_1 + m_2v_2 = (m_1 + m_2)V$

$1550(-10) + 2550*v_2 = (1550 + 2550)5.22$

$-15500 + 2550v_2 = 21402$

$2550v_2 = 36902$

$v_2 = 36902/2550 = 14.47 m/s$

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3 years ago

A girl travels 50m in 12s and then another 30m in 5s .Calculate her average speed?

Zanzabum

Answer:

4.71m/s

Explanation:

Average speed = Total distance travelled ÷ Total time taken.

80/17=4.71

4.71m/s

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3 years ago

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