Answer:
402 nm .
Explanation:
Let the wave length of unknown light be λ .
For fifth order maxima the condition is
path difference at the point of fringe = 5 λ
For red light of 670 nm , for 3 rd order maxima
path difference at the point of fringe = 3 x wave length
= 3 x 670 nm
From these two equations
5 λ = 3 x 670 nm
λ = 3 x 670 / 5 nm
= 402 nm .
It begins at the pinpoint with part vector 3.00 i ^ m. … with constant angular speed 1.50 rad/s in a circle of radius 3.00 m centered at the source.
<h3>How is the constant angular speed determined?</h3>
The angular velocity varies linearly at constant angular acceleration. As a result, for a given period, the average angular velocity is equal to half of the starting plus final angular velocity: -ω=ω0+ωf2. ω - = ω 0 + ω f 2 .
It is assumed that an object has a constant angular velocity when it moves in a circle at the same speed. As a result, when an object is traveling in an angular motion at the same speed, we can say that its angular velocity is constant.
To learn more about constant angular speed, refer to:
brainly.com/question/6860269
#SPJ4
C. 10 m/s
You divide 1000 m by 100 s.
1000/100 to find the velocity