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Nastasia [14]
3 years ago
14

Which characteristics of Earth’s orbit are in agreement with Kepler’s second law? Check all that apply.

Physics
2 answers:
Nataly [62]3 years ago
6 0

Here is a picture of the correct answers.

artcher [175]3 years ago
6 0

Explanation :  

The angular velocity of the planet in the elliptical orbit will vary. Its shows that the planet  travel slower when farther from the sun, then faster when closer to the sun.

1. Yes, Earth experiences the strongest gravitational force when it is closest to the Sun.

2. Yes,  Earth moves the greatest distance in thirty days when it is closest to the Sun.

3. Yes,  Earth travels with the slowest tangential speed when it is farthest from the Sun.

4. Yes,  Earth sweeps out the same area in the same time frame anywhere in its orbit

Kepler's second law : Kepler describe the motion of the planets around the sun. the line joining the planet and the sun sweeps out  the same area in the same time.

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A truck with a mass of 1370 kg and moving with a speed of 12.0 m/s rear-ends a 593 kg car stopped at an intersection. The collis
Elza [17]

Answer:

speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

Explanation:

Given:

mass of truck M = 1370 kg

speed of truck = 12.0 m/s

mass of car m = 593 kg

collision is elastic therefore,

Applying law of momentum conservation we have

momentum before collision = momentum after collision

1370×12 + 0( initially car is at rest) = 1370×v1+ 593×v2               ....(i)

Also for a collision to be elastic,

velocity of approach = velocity of separation

12 -0 = v2-v1                  ....(ii)

using (i) and (ii) we have

So speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

4 0
3 years ago
How long does it take a car travelling at 60 m.p.h to cover 5 miles?
k0ka [10]

Answer:

Time = 5 minutes

6 0
3 years ago
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A circle has an initial radius of 50ft when the radius begins decreasing at a rate of 2ft/s. what is the rate of change of the a
valkas [14]
The area of the circle with radius r is
A = πr²

The rate of change of area with respect to time is
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The rate of change of the radius is given as
\frac{dr}{dt} =-2 \,  \frac{ft}{s}
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When r = 10 ft, obtain
\frac{dA}{dt}|_{r=10 \, ft} = -40 \pi  \,  \frac{ft^{2}}{s}

Answer: - 40π ft²/s (or - 127.5 ft²/s)
7 0
4 years ago
If a rock were dropped from a building it would hit the ground with a certain kinetic energy and velocity. If it fell from a roo
STALIN [3.7K]

Answer:

no

Explanation:

because if you test it they hit the ground at the same time.

5 0
4 years ago
A 10 kg ball is traveling at the same speed as a 1 kg ball. Compared to the 10 kg ball, the 1 kg ball has
Zepler [3.9K]

The answer is the second option, or 1/10 the same momentum.

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3 years ago
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