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olga55 [171]
4 years ago
12

What do we mean by the event horizon of a black hole?

Physics
2 answers:
TEA [102]4 years ago
5 0
<h2>Answer:</h2>

The event horizon is the surface of a black hole, it is the border of space-time in which the events on one side of it can not affect an observer on the other side.  

That is, at this border also called "point of no return", nothing can escape (not even light) and no event that occurs within it can be seen from outside.

 

Flura [38]4 years ago
3 0

Answer:

The event horizon is an imaginary surface surrounding a black hole, where the escape velocity is equal to the speed of light. Therefore, nothing within that horizon can escape due to the attraction of a large gravitational field

Explanation:

No particle that falls within the event horizon comes out again, since a speed greater than light would be needed, and so far no particle can reach it. In this way, there is no way to look inside the event horizon. For this reason, black holes have no visible characteristics.

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What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh
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Answer:

a) R_s = 0.092

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Explanation:

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R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

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cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}

a) R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2

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b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

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