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kondaur [170]
3 years ago
9

4. Un móvil lleva una velocidad de 75 m/s, en dicho momento aplica los frenos durante tiempo de 15 segundos hasta detenerse. ¿cu

ál será la aceleración del frenado? ¿cuál es la distancia que recorre hasta detenerse?
Physics
1 answer:
brilliants [131]3 years ago
3 0

Answer:

a = 5 m / s²   and    x = 562.5 m

Explanation:

Let's apply the kinematics relations

          v = v₀ + at

          v² = v₀² + 2a x

In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative

           0 = v₀ - a t

           a = v₀ / t

let's calculate

           a = 75/15

           a = 5 m / s²

let's look for the distance

           0 = v₀² - 2a x

           x = v₀² / 2a

let's calculate

           x = \frac{75^2}{2 \  5 }

           x = 562.5 m

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Contact [7]

Answer:

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Explanation:

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P=2\pi r\\\Rightarrow r=\frac{P}{2\pi}\\\Rightarrow r=\frac{7000}{2\pi}\ m

a_c=\frac{v^2}{r}\\\Rightarrow a_c=\frac{\left(1.5\times 10^8\right)^2}{\frac{7000}{2\pi}}\\\Rightarrow a_c=2.0196\times 10^{13}\ m/s^2

Centripetal acceleration is 2.0196\times 10^{13}\ m/s^2

F_c=ma_c\\\Rightarrow F_c=1.67\times 10^{-27}\times 2.0196\times 10^{13}\\\Rightarrow F=3.37273\times 10^{-14}\ N

Force on protons is 3.37273\times 10^{-14}\ N

8 0
3 years ago
PLEASE HELP ASAP
DaniilM [7]

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4 0
3 years ago
What is the displacement of the object from 2 seconds to 6 seconds?
masya89 [10]

the answer would be 4

8 0
3 years ago
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Yakvenalex [24]
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8 0
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A 30.0 kg dolphin decelerates from 12.0 to 7.00 m/s in 2.60 s to join another dolphin in play. What average force (in N) was exe
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Answer:

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Explanation:

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That is    

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