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kondaur [170]
3 years ago
9

4. Un móvil lleva una velocidad de 75 m/s, en dicho momento aplica los frenos durante tiempo de 15 segundos hasta detenerse. ¿cu

ál será la aceleración del frenado? ¿cuál es la distancia que recorre hasta detenerse?
Physics
1 answer:
brilliants [131]3 years ago
3 0

Answer:

a = 5 m / s²   and    x = 562.5 m

Explanation:

Let's apply the kinematics relations

          v = v₀ + at

          v² = v₀² + 2a x

In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative

           0 = v₀ - a t

           a = v₀ / t

let's calculate

           a = 75/15

           a = 5 m / s²

let's look for the distance

           0 = v₀² - 2a x

           x = v₀² / 2a

let's calculate

           x = \frac{75^2}{2 \  5 }

           x = 562.5 m

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<u>Explanation:</u>

As displacement is the measure of difference between the final and initial points. In other words, we can say that displacement can be termed as the change in the position of the object irrespective of the path followed by the object to change the path. So

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