4. Un móvil lleva una velocidad de 75 m/s, en dicho momento aplica los frenos durante tiempo de 15 segundos hasta detenerse. ¿cu
1 answer:
Answer:
a = 5 m / s² and x = 562.5 m
Explanation:
Let's apply the kinematics relations
v = v₀ + at
v² = v₀² + 2a x
In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative
0 = v₀ - a t
a = v₀ / t
let's calculate
a = 75/15
a = 5 m / s²
let's look for the distance
0 = v₀² - 2a x
x = v₀² / 2a
let's calculate
x =
x = 562.5 m
You might be interested in
Answer:
-50 cm^3/min
Explanation:
The volume of the lollipop is given by
where r is the radius in centimeters.
To find how fast the volume changes, we need to find the rate of change of the volume, which is given by its derivative with respect to time:
(1)
where
dr/dt is the rate of change of the radius
We know that the circumference is
and it decreases by 1 cm per minute, so
(cm/min)
from which we find dr/dt:
Substituting into (1),
(cm^3/min)
And substituting r = 5, we find the rate of change of the volume when the radius is 5 cm:
(cm^3/min)
Answer:
E1 = 10.15 * 10^4 N/C
E2 = 0
E3 = 10.15 *10^4 N/C
Explanation:
Given data:
Two 13 cm-long thin glass rods ( L ) = 0.13 m
charge (Q) = +11nC
distance between thin glass rods = 4 cm .
<u>Calculate the electric field strengths </u>
electric charge due to a single glass rod in the question ( E ) =
equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced
applying equation 1 to determine E1
E1 =
( distance from 1 rod is 0.01 m and from the other rod is 0.03 )
=
= 10.15 * 10^4 N/C
applying equation 1 to determine E2
E2 =
therefore E2 = 0
E1 = E3
hence E3 = 10.15*10^4 N/C