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Rama09 [41]
2 years ago
8

Two forces of magnitude 8N and 4N act at right angle to each other. The angle between the resultant and the 8N force is?

Physics
1 answer:
Marta_Voda [28]2 years ago
4 0

Answer:

Draw the vector triangle (head to tail)

Let 8 be adjacent and 4 the opposite side

tan theta = 4 / 8 = .5

theta = 26.6 deg

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W, because as time is moving up at a consistent rate the speed is as well, creating the straight line.
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3 years ago
A person in the back of a pick-up moving at 20 m/s relative to the Earth, throws a baseball with a speed of 15 m/s in a directio
Bumek [7]

Answer:

This is known as a Galilean transformation where

V' = V - U

Where the primed frame is the Earth frame and the unprimed frame is the frame moving with respect to the moving frame

V - speed of object in the unprimed frame

U - speed of primed frame with respect to the unprimed frame

Here we have:

V = -15 m/s        speed of ball in the moving frame (the truck)

U =  -20 m/s        speed of primed (rest) frame with respect to moving frame

So  V' = -15 - (-20) = 5 m/s

It may help if you draw a vector representing the moving frame and then add

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3 0
3 years ago
I need help the option for D is the golfball isnt accelerating
algol13

Answer:

es b

Explanation:

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8 0
3 years ago
Spiral fracture of bone: Spiral fracture of bone occurs due to twisting of the limb, and is a very common skiing accident. The f
Pavlova-9 [17]

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

<u>a) Determine the principal stresses and shear stress</u>

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

Hence principal stresses = 32.0060 ± 0.62

б1 = 32.62mPa  

б2 = 31.38mPa

attached below is the remaining part of the solution

3 0
3 years ago
Peter left town A at 13:30 and travelled towards town B at an average speed of 40mph. At 13:45 Philip left town A for town B at
skad [1K]

Answer:

fbddb

Explanation:

dsbse

8 0
2 years ago
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