Does the size of a paper airplane affect how far it flies

An object of mass 5 kilograms is acted upon by the forces F and F2 as shown.

Alekssandra [29.7K]

Answer:

61 N

Explanation:

Sum of forces in the x direction:

∑F = ma

F₂ cos (-55°) − 35 N = 0

F₂ cos (-55°) = 35 N

F₂ = 61 N

3 0

3 years ago

What is the thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm ?

Marizza181 [45]

The thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm is <u>200 nm.</u>

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The wavelength of mild, λ = 500 nm

= 500 x 10^-9 m

Refractive index of oil, n1 = 1.25

Refractive index of water, n2 = 1.33

The thickness of the movie, d =?

For a sturdy mirrored image, m = 1

Wavelength, λ= 2 n1 d / m

Thickness, d = λ m / 2 n1

= 500 x 10 -9 * 1 / ( 2 * 1.25 )

= two hundred x 10 -nine m

= 2 hundred nm.

Wavelength is the gap between the same factors (adjacent crests) within the adjacent cycles of a waveform signal propagated in space or alongside a wire. In wireless systems, this duration is usually specified in meters (m), centimeters (cm), or millimeters (mm).

Wavelength may be defined as the space between two successive crests or troughs of a wave. it is measured within the route of the wave.

Wavelength is the distance among two adjacent crests or troughs of a waveform signal propagated in space or along a wire. The wavelength of a wave is usually specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is inversely related to frequency.

Learn more about Wavelength here brainly.com/question/10750459

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3 0

2 years ago

What is the meaning of sound media component

Artist 52 [7]

Answer:

prerecorded magnetic tapes used for noncommercialplayback of sound on audio equipment.

Explanation:

study hard:)

5 0

3 years ago

Dharna is said to be concentration it is true or false

Lelechka [254]

dharna is said to be concentration.. it is true

5 0

2 years ago

A mass is hung from a spring and set in motion so that it oscillates continually up and down. The velocity v of the weight at ti

otez555 [7]

To solve the problem it is necessary to identify the equation in the manner given above.

This equation corresponds to the displacement of a body under the principle of simple harmonic movement.

Where,

$\xi = Acos(\omega t +\phi)$

PART A) Our equation corresponds to

$y = -5cos(4\pi t)$

Therefore the value of omega is equivalent to that of

$\omega = 4\pi$

From the definition we know that the period as a function of angular velocity is equivalent to

$T = \frac{2\pi}{\omega}$

$T = \frac{2\pi}{4\pi}$

$T = \frac{1}{2}$

This same point is the equivalent of the maximum point of the speed that the body can reach, since the internal expression of the $cos\theta$ Is equivalent to . So the maximum speed that the body can reach is,