Answer:
1) Given acceleration due to gravity as 10N/kg
N/kg is the same as m/s². From W=mg
making g subject ... you have g = W/m
where m is in kg and W is in N
hence we have N/kg
So g=10ms-²
Gravitational Potential Energy=mgh
At height 4m
PE=6 x 10 x 4
=240J.
At height 6m
PE=6 x 10 x 6
=360J.
2) KE=1/2mv²
=1/2 x 6 x 5² =75J
When the speed is doubled... it becomes 2x
so V = 2x5=10ms-¹
KE=1/2 x 6 x 10² =300J.
3) KE=1/2mv²
KE is given as 100J
mass=0.5kg
Making V the subject
you have v² =2KE/m
v²=2 x 100/0.5
v²=400
taking square root
v=20ms-¹.
Have a great day✌
Answer: The answer is "C"
Explanation:
The electromagnetic waves are arranged in the increasing wavelength and energy by the following order;
Radio waves has the lowest energy and wavelength but of the highest frequency.
The Infra-red rays follows the visible light follows, the ultraviolet ray follows, the X-ray follows and then the Gamma-ray has the highest energy and wavelength but the lowest frequency.
Therefore the answer is C, radio, infra, visible, ultraviolet, x-ray, gamma.
<u>I have assumed a weight of 120 N on Earth.</u>
Answer:
<em>The object weighs 20 N on the moon</em>
Explanation:
Weight
The weight of an object depends on the mass m of the object and the acceleration of gravity g of the place they are in.
The formula to calculate the weight is:
W = m.g
If g_e is the acceleration of gravity on Earth, and g_m is the acceleration of gravity on the moon, we know:
Dividing by ge:
An object of weight We=120 N on planet Earth has a mass of:
Multiplying by gm:
Substituting the ratio of accelerations of gravity:
Since m.gm is the weight on the Moon Wm:
The object weighs 20 N on the moon
Answer:He lifts 2 meters
Explanation:We are trying to find the distance. The formula for distance is W/Force. 50 is our amount of work. 25N is how much force was used. Divide the work bye the force. 50/25=2M
Answer:
0.546 ohm / μm
Explanation:
Given that :
N = 1.015 * 10^17
Electron mobility, u = 3900
Hole mobility, h = 1900
Ng = 4.42 x10^22
q = 1.6*10^-19
Resistivity = 1/qNu
Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)
= 0.01578880889 ohm /cm
Resistivity of germanium :
R = 1 / 2q * sqrt(Ng) * sqrt(u*h)
R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)
R = 1 /0.0001831
R = 5461.4964 ohm /cm
5461.4964 / 10000
0.546 ohm / μm
