Answer:
Explanation:
Thinking process:
Let:
distance = speed × time
for the hare:
for the tortoise:
Let the length of the shell be s. Then the two are related. So:
Let's say the hare ran at x times the speed of the tortoise:
So, the equation still holds :
You divide 120 and 72 and get 1.67 repeated i think
Answer:
1800 seconds
Explanation:
Given,
Distance ( d ) = 18 km
Velocity ( v ) = 10 m/s
To find : Time ( t ) = ?
Distance in km need to be converted to m.
1 km = 1000 m
18 km
= 18 x 1000
= 18000 m
So,
d = 18000 m
Formula : -
v = d / t
t = d / v
= 18000 / 10
t = 1800 seconds.
Therefore,
1800 seconds long, it will take to cover a distance of 18 km.
Answer:
1.) Time = 3.5 seconds
2.) Range = 21 m
3.) Velocity = 34.8 m/s
Explanation:
Given that the
Height h = 60 m
Initial velocity U = 6 m/s
1.) The time taken to hit the river for a single droplet of water can be achieved by using second equation of motion
h = Ut + 1/2gt^2
Let assume that the water drops from rest. Therefore, U = 0
60 = 1/2 × 9.8t^2
60 = 4.9t^2
t^2 = 60/4.9
t^2 = 12.24
t = sqrt (12.24)
t = 3.5s
2.) The range of the projectile for a single droplet of water will be calculated by using the formula
R = Ut
Range R = 6 × 3.5 = 20.99
Range = 21 m
3.) The velocity (diagonal) when it hits the water.
Using third equation of motion
V^2 = U^2 + 2gH
Substitute values into the equation
V^2 = 6^2 + 2 × 9.8 × 60
V^2 = 36 + 1176
V^2 = 1212
V = sqrt (1212)
V = 34.8 m/s
Answer:
Explanation:
Let f is frequency of of the guitar string
Frequency of tuning fork is given 487 Hz
Beat frequency is difference frequencies of guitar string and the tuning fork
It could be
(f - 487Hz)
or
(487Hz-f)
As it is mentioned that as the frequency of guitar string increases the beat frequency decreases
So the beat frequency is given as
