<span>It is false that it is the obligation of researchers to review and comment on the research of other researchers. It is not their obligations - they don't have to do it, although they can if they want to and if they are allowed by the author him or herself. However, they are not bound by law or something like that to do this, it's just due to their kindness or genuine interest that they do this.</span>
<span>Mouth,Pharynx,Larynx.Trachea,Bronchi and Bronchioles,Lungs,<span>Muscles of Respiration.</span></span>
The formula that is usually used for the calculation of power is the product of force applied and the speed at which the action is done. That is,
P = Fv
We let d be the distance covered and the equation for power would be,
P = (500 N)(d/240 s)
P = 2.08d
The correct answer is :
According to classical electrodynamics, light energy is a wave that is absorbed by atoms in a manner similar to how an object absorbs radiant heat. So, the atoms of a metal would absorb more energy the brighter the light was. It would be feasible for an electron in a metal to break free from its atoms if it received enough energy from the incoming wave. The more energy absorbed, the more energetic the metal's released electrons would be. Additionally, no electrons could conceivably be ejected until each atom had enough light energy. Light intensity was far more important than light frequency.
In many respects, the photo-electric effect contradicted this strategy:
- If the light was below a specific frequency, no matter how bright it was, no electrons were released. Increased light intensity increased the number of electrons that were released, but not their energy, if the light was above this frequency.
- Regardless of how weak the light was, electrons were nearly immediately emitted from the metal.
- Even though the intensity of the light was reduced, an increase in its frequency led to more energising electrons leaving the metal.
To learn more about photo-electric effect refer the link:
brainly.com/question/25630303
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Answer:
Explanation:
What we are basically looking for here is how long it takes the first stone to hit the water. We have everything we need to figure that out. We will use the equation
Δx = . Filling in, we will solve for t, the time is takes the first stone to hit the water (which is the same for both since they both hit the water at the same time):
which is a quadratic that we will have to factor. Get it into standard form, setting it equal to 0:
and factor to get that
t = 3.2 s and t = -2.8 s
Since time can't ever be negative, it takes 3.2 s for the stones to hit the water.
