Answer:
Explanation:
The magnitude on the charge at the bottom-left corner due to the charge on the top vertex of the triangle will act along the +ve x-axis and the +ve y-axis.
From Coulomb's law the magnitude of the forces on the charge at the bottom-left corner, due to the charge on the top vertex of the triangle are cos 60, and
The magnitude on the charge due to the charge at the bottom-right corner will only act in the -ve x-axis, since they repel each other (like charges repel). The magnitude is
The angle made by the upper charge to the charge we're considering is 60° with the horizontal.
The total force on the charge along the x-axis is
= cos 60 -
= -
==> -
For the y-axis, we have
= sin 60
=
The resultant force is
The common factors between the two x-axis force, and the y-axis force is
, we put this outside the square root (squaring this and square rooting will give us the initial value)
=
=
==>
the magnitude of the electric force on the charge at the bottom left-hand vertex of the triangle due to the other two charges is
=
Answer:
The correct answer is:
(a)
(b)
Explanation:
The given values are:
Power of Laser beam,
= 10 mW
on converting it, we get
=
=
Spot's diameter,
= 0.62 μm
=
Now,
(a)
The intensity of light will be:
⇒
or,
⇒
On substituting the values, we get
⇒
⇒
(b)
The amplitude of electric field will be:
⇒
or,
⇒
On substituting the values, we get
⇒
⇒
As far as I remember the nuclear power is derived from a nuclear <span>A)fusion </span>chain reaction. I think it's correct.
Answer:
128 m
Explanation:
From the question given above, the following data were obtained:
Horizontal velocity (u) = 40 m/s
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Horizontal distance (s) =?
Next, we shall determine the time taken for the package to get to the ground.
This can be obtained as follow:
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
50 = ½ × 9.8 × t²
50 = 4.9 × t²
Divide both side by 4.9
t² = 50 / 4.9
t² = 10.2
Take the square root of both side
t = √10.2
t = 3.2 s
Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:
Horizontal velocity (u) = 40 m/s
Time (t) = 3.2 s
Horizontal distance (s) =?
s = ut
s = 40 × 3.2
s = 128 m
Therefore, the package will land at 128 m relative to the plane