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galben [10]
3 years ago
14

a light beam that hits a mirror at an angle of 36°... what is the Angle of Incidence? Angle of Reflection?​

Physics
1 answer:
Kipish [7]3 years ago
6 0

Angle of incidence is 36° and so is the reflection. Both angles are equal.

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A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 6.8 m. The
Ber [7]

Answer:

1. v=14.2259\ m.s^{-1}

2. F_T=25.8924\ N

3. \lambda=29.6373\ m

Explanation:

Given:

  • mass of slinky, m=0.87\ kg
  • length of slinky, L=6.8\ m
  • amplitude of wave pulse, A=0.23\ m
  • time taken by the wave pulse to travel down the length, t=0.478\ s
  • frequency of wave pulse, f=0.48\ Hz=0.48\ s^{-1}

1.

\rm Speed\ of\ wave\ pulse=Length\ of\ slinky\div time\ taken\ by\ the\ wave\ to\ travel

v=\frac{6.8}{0.478}

v=14.2259\ m.s^{-1}

2.

<em>Now, we find the linear mass density of the slinky.</em>

\mu=\frac{m}{L}

\mu=\frac{0.87}{6.8}\ kg.m^{-1}

We have the relation involving the tension force as:

v=\sqrt{\frac{F_T}{\mu} }

14.2259=\sqrt{\frac{F_T}{\frac{0.87}{6.8}} }

202.3774=F_T\times \frac{6.8}{0.87}

F_T=25.8924\ N

3.

We have the relation for wavelength as:

\lambda=\frac{v}{f}

\lambda=\frac{14.2259}{0.48}

\lambda=29.6373\ m

8 0
3 years ago
Mechanical energy is the sum of ________ energy and potential energy.apex
crimeas [40]
Mechanical energy is the sum of kinetic energy and potential energy
6 0
3 years ago
How much time would it take for the sound of thunder to travel 2000 meters if sound travels of 330 meters per sec
Lubov Fominskaja [6]
2000÷330=6.06 repatant so the answer would be about 6.06 seconds
4 0
3 years ago
Read 2 more answers
A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula.
expeople1 [14]

Answer:

Magnitude = 3.64 × 10^6  

စ = 43.9°

Explanation:

given data

ship to travel = 1.7 × 10^6    kilometers

turn = 70°

travel an additional = 2.7 × 10^6   kilometers

solution

we will consider here

Px = 1.7 × 10^6  

Py = 0

Qx =2.7 × 10^6  cos(70)

Qy= 2.7 × 10^6  sin(70)

so that

Hx = Px + Qx    ............1

Hx = 2.62 × 10^6  

and

Hy = Py + Qy      ..........2

Hy = 2.53 × 10^6  

so Magnitude = \sqrt{((2.62 \times 10^6  )^2+(2.53 \times 10^6)^2)}

Magnitude = 3.64 ×  

so direction  will be

tan စ = Hy ÷ Hx    ......................3

tan စ  = \frac{2.53}{2.62}

tan စ  = 0.9656

စ = 43.9°

3 0
3 years ago
Factors that affect acceleration due to gravity.<br>​
hram777 [196]

Answer

Factors Affecting Acceleration Due to Gravity

 

(1) Position on the planetary surface, it is higher at the axis (poles),

(2) Mass of the planet, higher with planets of larger masses

(3) Distance between object and the centre of planet, the larger the distance, the smaller the acceleration due to gravity.

Mark me as Brainlist if this answer is helpful for you

8 0
3 years ago
Read 2 more answers
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