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drek231 [11]
4 years ago
5

At a job interview, the most effective way to prove your proficiency to a prospective employer is to show that you have 

Chemistry
1 answer:
inna [77]4 years ago
7 0
The most effective way to showcase your proficiency in a job interview is to show certificates. For example, in this case, option D. certification as an electronics technician. Option A's online research experience is menial as well as using own test equipment as this renders hassle and futile. Membership cannot guarantee job proficiency, too. Answer is D.
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A gram is one million times larger than a microgram but one billion times smaller than a _______________.
Len [333]
Answer : A hectogram

Explanation:
6 0
3 years ago
Use the reaction, which produces ammonia, to answer the question.
zepelin [54]

This problem is providing us with the chemical equation depicting the production of ammonia from nitrogen and hydrogen at equilibrium and asks for the correct change when the concentration of nitrogen is increased. At the end, the answer is the forward reaction would increase to start reducing the concentration of N2.

<h3>Chemical equilibrium</h3>

In chemistry, chemical reactions not always reach a 100-% conversion when reactants get in contact in order to carry out the chemical reaction. Thus, there is a point wherein the concentrations remain the same and is called equilibrium.

In such a way, for this problem, we have the following chemical reaction at equilibrium:

N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)

Now, according to the Le Ch.atelier's principle, an increase in the concentration of any species, shifts the equilibrium away from it, which means that if we increase the concentration of nitrogen, a reactant, the forward reaction will be favored.

Thereby, the correct answer is "the forward reaction would increase to start reducing the concentration of N2".

Learn more about chemical equilibrium: brainly.com/question/26453983

4 0
2 years ago
Hydrogen peroxide is a powerful oxidizing agent; it is used in concentrated solution in rocket fuel and in dilute solution in ha
Anestetic [448]

The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.

Co = 10pd/M

Where;

Co = concentration = ?

p = percent of the hydrogen peroxide =  30%

d = Density of hydrogen peroxide =  1.39 g/ml

M = Molar mass  = 34 g/mol

Substituting values;

Co = 10 × 30 ×  1.39/34

Co = 12.26 M

The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.

Learn more: brainly.com/question/6111443

4 0
3 years ago
Which two processes are responsible for water's transfer of transfer of energy in the atmosphere and hydrosphere?
Liula [17]
Oooo! I love this :P
D. Precipitation and evaporation :P
When I rains the clouds travel from place 2 place raining in different places bringing water.
THE WATER CYCLE 4 ONE THING

7 0
3 years ago
The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 1.751 g sample of e
fredd [130]

<u>Answer:</u> The empirical formula for the given compound is C_{4}H_{10}O

<u>Explanation:</u>

The chemical equation for the combustion of ether follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=4.159g

Mass of H_2O=2.128g

Mass of sample = 1.751 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 4.159 g of carbon dioxide, \frac{12}{44}\times 4.159=1.134g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 2.128 g of water, \frac{2}{18}\times 2.128=0.236g of hydrogen will be contained.

Mass of oxygen in the compound = (1.751) - (1.134 + 0.236) = 0.381 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.134g}{12g/mole}=0.0945moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.236g}{1g/mole}=0.236moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.381g}{16g/mole}=0.0238moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0238 moles.

For Carbon = \frac{0.0945}{0.0238}=3.97\approx 4

For Hydrogen = \frac{0.236}{0.0238}=9.91\approx 10

For Oxygen = \frac{0.0238}{0.0238}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 10 : 1

Hence, the empirical formula for the given compound is C_{4}H_{10}O

7 0
3 years ago
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