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4 years ago

At a job interview, the most effective way to prove your proficiency to a prospective employer is to show that you have

1 answer:

7 0

The most effective way to showcase your proficiency in a job interview is to show certificates. For example, in this case, option D. certification as an electronics technician. Option A's online research experience is menial as well as using own test equipment as this renders hassle and futile. Membership cannot guarantee job proficiency, too. Answer is D.

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A 2.50-l flask contains a mixture of methane (ch4) and propane (c3h8) at a pressure of 1.45 atm and 20°c. when this gas mixture

Cerrena [4.2K]

Answer:- Mole fraction of methane in the original gas mixture is 0.854.

Solution:- From given volume, pressure and temperature, we could calculate the total moles of the gaseous mixture of methane and propane using ideal gas law as:

PV = nRT

$n=\frac{PV}{RT}$

V = 2.50 L

P = 1.45 atm

T = 20 + 273 = 293 K

Let's plug in the values in the equation:

$n=(\frac{1.45*2.50}{0.0821*293})$

n = 0.151

Let's say the solution has X moles of methane. Then moles of propane would be = (0.151 - X)

The combustion equations of methane and propane are:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

From methane balanced equation, there is 1:1 mol ratio between methane and carbon dioxide. So, X moles of methane would produce X moles of carbon dioxide.

From balanced equation of propane, there is 1:3 mol ratio between propane and carbon dioxide. So, (0.151 - X) moles of propane would give 3(0.151 - X) moles of carbon dioxide.

So, total moles of carbon dioxide that we would get from methane and propane combustion are:

X + 3(0.151 - X)

From given data, 8.60 g of carbon dioxide are formed by the combustion of gas mixture.

moles of Carbon dioxide = $8.60g(\frac{1mol}{44g})$

moles of carbon dioxide = 0.195 mol

Hence, 0.195 = X + 3(0.151 - X)

Let's solve this for X as:

0.195 = X + 0.453 - 3X

0.195 = 0.453 - 2X

2X = 0.453 - 0.195

2X = 0.258

$X=\frac{0.258}{2}$

X = 0.129

So, there are 0.129 moles of methane in the mixture.

moles of propane = 0.151 - 0.129 = 0.022

mole fraction of methane = $\frac{moles of Methane}{total moles}$

mole fraction of methane = $\frac{0.129}{0.151}$

mole fraction of methane = 0.854

Hence, the mole fraction of methane gas in the original gas mixture is 0.854.

6 0

3 years ago

Help on math question please (will mark as brainliest)

aliya0001 [1]

Answer:paragrph 2 drought caused by cutting tress impacts earth system with climate change and global. learing land short term breathing for popel.long term affect erosion

Explanation:

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4 years ago

At what time of the year can the sun be found at the zenith

Step2247 [10]

Answer: The Sun Could Be Seen Once during the year when north of the equator.

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3 years ago

Determine the enthalpy for the reaction A+B --> C If we know the following:

PolarNik [594]

Explanation:

here is the answer to the question

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3 years ago

What is the energy of a photon having a wavelength of 2.60 ✕ 10-8 m?<br> J

zvonat [6]

The energy of a photon : 7.645 x 10⁻³⁴ J

<h3>Further explanation </h3>

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

$\large{\boxed{\bold{E\:=\:h\:.\:f}}}$

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ , Hz

c = speed of light

= 3.10⁸ m/s

λ = wavelength ,m

wavelength λ of 2.60 ✕ 10⁻⁸ m

The energy :

$\tt E=h.\dfrac{c}{\lambda}\\\\E=6.626.10^{-34}\times \dfrac{3\times 10^8}{2.6\times 10^{-8}}\\\\E=7.645\times 10^{-34}~J$

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3 years ago