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AleksandrR [38]
3 years ago
5

I need help! Thanks!

Chemistry
2 answers:
Tems11 [23]3 years ago
4 0

Answer:

C. As speed increases, kinetic energy increase exponentially

Explanation:

As you can see on the graph, the further right we move on the x-axis, the higher the values on the y-axis. This means that as one value increases, the other value also increases. The only answer choice that says this is C.

Hope this helps :)

Anit [1.1K]3 years ago
4 0

is C because i did it on the quiz

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In which Colorado Rockies scenario was there more erosion? Why was there more erosion in the scenario?
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Answer:

Explanation:

The Erosion in the Colorado Rookies Scenario that record a ready rain were more than the other scenario in the same area with just a drizzle. The Erosion is much in the Colorado Rockies Scenario that record a steady rain because the volume of the rivers has goes up compare to that of the Scenario with just a drizzle. As a result of the increased in the amount of the rivers bank that is flowing, the river flows more faster which helps in the transportation of the sediments or Erodes.

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An acid has an acid dissociation constant of 2.8 10–9. What is the base dissociation constant of its conjugate base?
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The answer is 3.6 x 10^-6
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The electronic configuration of phosphorous is 2.8.5. Explain, in terms of its electronic configuration, why phosphorus is in gr
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Explanation:

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Lawrencium-262 has a half-life of 4 hr. How much of a 40 mg sample remains after 12 hours?
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5 mg

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3 0
2 years ago
calculate q for the following: 125.0 ml of 0.0500 m pb(no3)2 is mixed with 75.0 ml of 0.0200 m nacl at 25oc chegg
alexandr402 [8]

The value of Q for 125.0 ml of 0.0500 m Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl at 25°C is 2.11 × 10^(-6).

Aa we know that, 125mL of 0.06M Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl.

Given, T = 25°C.

<h3>Chemical equation:</h3>

Pb(NO3)2 + NaCl ---- NaNO3 + PbCl2

PbCl2 in aqueous solution split into following ions

PbCl2 ------ Pb(+2) + 2Cl-

Q = [Pb(+2)] [Cl-]^2

The Concentration of Pb(+2) ions and Cl- ions can be calculated as

[Pb(+2)] = 0.06 × 125/200

= 0.0375

[Cl-] = 0.02 × 75/200

= 0.0075

By substituting all the values, we get

[0.0375] [0.0075]^2

= 2.11 × 10^(-6).

Thus, we calculated that the value of Q for 125.0 ml of 0.0500 m Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl at 25°C is 2.11 × 10^(-6).

learn more about Ions:

brainly.com/question/13692734

#SPJ4

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