All categories

3 years ago

What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?

Chemistry

1 answer:

Inessa05 [86]3 years ago

8 0

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

H = 1g/mol

N = 14g/mol

O = 16g/mol

Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

= 168 + 22 + 56 + 128

= 374u

Empirical weight:

Empirical formula:

C₁₄ H₂₂ N₄ O₈

14 : 22 : 4 : 8

divide by 2:

7 : 11 : 2 : 4

empirical formula C₇H₁₁N₂O₄

empirical weight = $\frac{molecular weight}{2}$ = $\frac{374}{2}$ = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

You might be interested in

Which substance is important in making plastics?

QveST [7]

Based on the compounds given, I can say that the substance that is considered essential in the plastic making is NITRIC ACID. This substance is also known as aqua fortis and spirit of niter wherein this decomposes into oxides of nitrogen and water. The answer would be the last option. Hope this helps.

8 0

3 years ago

Read 2 more answers

To create an ion you simply need to add or take away an electron true or false

BigorU [14]

Answer:

True

Explanation:

ion: an atom or molecule with a net electric charge due to the loss or gain of one or more electrons.

5 0

3 years ago

Read 2 more answers

HELPPPP MEEE PLEASEEE!!!!!!

MrRa [10]

Mass =70 ( Mass of protons=1 ,Mass of neutrons =1, Mass of electron =0.0005(can be ignored))
Therefore, 40 +30=70
Charge= -2 ( it is taking in/attracting electrons to its shell) base on the proton number you are able to identify if it is attracting or releasing an electron, if the electron number is more than proton number then it is attracting therefore resulting in a negative charge vice versa for releasing an electron.

5 0

3 years ago

If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H2SO4(aq)? For your ans

Alik [6]

Question is incomplete, complete question is;

A 34.8 mL solution of $H_2SO_4$ (aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).

$H_2SO_4(aq)+2NaOH(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of $H_2SO_4(aq)$ ? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.

Answer:

0.044 M is the molarity of $H_2SO_4$ (aq).

Explanation:

The reaction taking place here is in between acid and base which means that it is a neutralization reaction .

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_1,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=34.8 mL\\n_2=1\\M_2=0.15 M\\V_2=20.4 mL$

Putting values in above equation, we get:

$2\times M_1\times 34.8 mL=1\times 0.15 M\times 20.4 mL\\\\M_1=\frac{1\times 0.15 M\times 20.4 mL\times 10}{2\times 34.8 mL}=0.044 M$

0.044 M is the molarity of $H_2SO_4$ (aq).

4 0

3 years ago

Determine whether each of the following salts will form a solution that is acidic, basic, or pH-neutral. Drag the appropriate it

Aleks04 [339]

Answer:

AI(NO₃)₃ → Acidic pH < 7

CH₃NH₃CN → Neutral pH = 7

NaCIO → Basic pH > 7

CH₃NH₃CI → Acidic pH < 7

NaNO₃ → Neutral pH = 7

Explanation:

First of all we dissociate the salts:

Al(NO₃)₃ → Al³⁺ + 3NO₃⁻

Nitrate anion comes from the nitric acid which is strong, so the anion is the conjugate weak base. It does not react to water, but the Al is an special case. Aluminum as a cathion comes from the Al(OH)₃ which is a base but this compound can also react as an acid, it is called amphoterous.

Al³⁺ + H₂O ⇄ Al(OH)²⁺ + H⁺

Aluminium cathion reacts to water in order to produce a complex and to give protons to the medium, so the salt is acid.

CH₃NH₃CN → CH₃NH₃⁺ + CN⁻

Both ions come from a weak base and a strong acid, so both ions are the conjugate strong base and acid, respectively. They can make hydrolysis to water so the salt is neutral.

CH₃NH₃⁺ + H₂O ⇄ CH₃NH₂ + H₃O⁺ Ka

CN⁻ + H₂O ⇄ HCN + OH⁻ Kb

NaCIO → Na⁺ + ClO⁻

Sodium cathion, comes from the strong base NaOH so it is does not react to water. It is the conjugate weak acid. Hypochlorite comes from the weak acid, so it can hydrolyse to water.

ClO⁻ + H₂O ⇄ HClO + OH⁻ Kb

Hypochlorous acid is formed giving OH⁻ to medium, so the salt is basic.

CH₃NH₃CI → CH₃NH₃⁺ + Cl⁻

Chloride comes from the strong acid HCl. It does not react to water.

Methylammonium comes from the weak base, methylamine so it can react to water in order to make hydrolysis. The salt will be acidic.

CH₃NH₃⁺ + H₂O ⇄ CH₃NH₂ + H₃O⁺ Ka

NaNO₃ → Na⁺ + NO₃⁻

Both ions come from a strong base and acid, so they are the conjugate base and acid, respectively. As they do not make hydrolisis in water, the salt will be neutral.

5 0

3 years ago