The type of bond most likely formed in nitrous oxide would be a covalent bond..
Answer:
1.0 L
Explanation:
Given that:-
Mass of
= 
Molar mass of
= 64.099 g/mol
The formula for the calculation of moles is shown below:

Thus,


According to the given reaction:-

1 mole of
on reaction forms 1 mole of 
0.0396 mole of
on reaction forms 0.0396 mole of 
Moles of
= 0.0396 moles
Considering ideal gas equation as:-

where,
P = pressure of the gas = 742 mmHg
V = Volume of the gas = ?
T = Temperature of the gas = ![26^oC=[26+273]K=299K](https://tex.z-dn.net/?f=26%5EoC%3D%5B26%2B273%5DK%3D299K)
R = Gas constant = 
n = number of moles = 0.0396 moles
Putting values in above equation, we get:

<u>1.0 L of acetylene can be produced from 2.54 g
.</u>
Since K3 is greater than 1, the reaction is thermodynamically favorable.
Data;
- FeF2 is in an acidic solution
- K2 > 1 is thermodynamically favorable
- k3 > 1 is not thermodynamically favorable
- K1<1 is not thermodynamically favorable
<h3>Hess Law</h3>
This states that the heat change in a given chemical reaction is the same irrespective of the number of process in which the reaction is effected.
Using Hess Law;

substituting this using Gibbs law,

Since K3 is greater than 1, the reaction is thermodynamically favorable.
Learn more on Hess law here;
brainly.com/question/12895682
A covalent bond is stronger than an ionic bond because the covalent bond doesn’t separate in water
Answer:
pH is 7.60
Explanation:
Let's think the equations:
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
As every weak acid, we make an equilbrium
The salt is dissociated in solution
NaClO → Na⁺ + ClO⁻
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
Initially 0.3m 0.35m
We have the moles of acid, and the moles of conjugate base.
Reacts x X X
Some amount has reacted, so I obtained (in equilibrium) the moles of base + that amount, and the same amount for H₃O⁺ (ratio is 1:1)
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
0.3 - x 0.35 + x x
Let's make the expression for Ka
Ka = [ClO⁻] . [H₃O⁺] / [HClO]
(we don't add water, because it is included in Ka)
2.9x10⁻⁸ = (0.35+x).x / (0.3-x)
Ka is in order of 10⁻⁸, I can assume that 0.3-x is 0.3 and 0.35 +x =0.3
2.9x10⁻⁸ = (0.35)x / (0.3)
(2.9x10⁻⁸ . 0.3) /0.35 = x
2.48x10⁻⁸ = x
This is [H₃O⁺]
For pH = - log [H₃O⁺]
pH = 7.60