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Alja [10]
4 years ago
15

Which of the following does not serve as a way to neutralize the charge in a body?

Physics
1 answer:
Brrunno [24]4 years ago
5 0

Answer:

B. Adding more protons to a positively charged body until the number of protons matches the number of electrons

Explanation:

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What is the acceleration of a car initially traveling at -5m/s and<br> reaching -22m/s in 3s.
lozanna [386]

Answer:

a=-5.67\ m/s^2

Explanation:

Given that,

Initial velocity, u = -5 m/s

Final velocity, v = -22 m/s

Time, t = 3s

We need to find the acceleration of the car. The formula of it is given by :

Acceleration,

a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2

So, the acceleration of the car is -5.67\ m/s^2.

4 0
3 years ago
A train travels for 120 seconds (s) at a speed of 50 meter per second (m/s). What was the distance (m) that it travelled?
Ivahew [28]

Answer:

2

Explanation:

50 times 2

6 0
3 years ago
A student drops an object from rest above a force plate that records information about the force exerted on the object as a func
OLEGan [10]

Answer:

A. The mass of the object

Explanation:

p = mv

p = momentum

m = mass

v = velocity

5 0
3 years ago
Read 2 more answers
A pipe of length 4 m open at one end resonates with the 11th harmonic of a frequency. What is the wavelength of the frequency?
Brilliant_brown [7]
You use the equation wavelength= 4 x length of pipe/ number of the harmonic so your wavelength is 1.45. 
5 0
4 years ago
A basketball player jumps straight up for a ball. To do this, he lowers his body 0.300 m and then accelerates through this dista
cluponka [151]

Answer:

4.20214231077 m/s

29.429 m/s²

4316.29 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of player = 110 kg

Equations of linear motion

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.81\times 0.9}\\\Rightarrow u=4.20214231077\ m/s

The velocity is 4.20214231077 m/s

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{4.20214231077^2-0^2}{2\times 0.3}\\\Rightarrow a=29.429\ m/s^2

The acceleration is 29.429 m/s²

Force is given by

F=m(a+g)\\\Rightarrow F=110(29.429+9.81)\\\Rightarrow F=4316.29\ N

The force he exerts is 4316.29 N

6 0
3 years ago
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