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dimulka [17.4K]
3 years ago
10

What is the volume of the shape below? Help me plzzzz

Physics
1 answer:
QveST [7]3 years ago
3 0

Answer:

20cm

Explanation:

2 × 5 × 2 = 20

Hope this helps.

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*PLZ HELP ASAP* Saturn and Jupiter both complete one rotation in about____hours.
Debora [2.8K]

Answer:

10

Explanation: Earth takes 24 hours to complete one spin, and Mars takes 25 hours. The gas giants rotate really fast. Jupiter takes just 10 hours to complete one rotation. Saturn takes 11 hours, Uranus takes 17 hours, and Neptune takes 16 hours.

8 0
3 years ago
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What is the name for the layer of cells at the back of the eye that contains photoreceptors?
Alona [7]
B.) The retina is the layer containing t<span>he light sensing nerve cells (rods and cones)

The lens helps the eye focus light on the retina, the cornea is the outer transparent structure that covers the iris and helps the eye focus, and the pupil is the opening through which light enters the eye.</span>
4 0
3 years ago
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a vector a has components a x equals -5.00 m in a y equals 9.00 meters find the magnitude and the direction of the vector
Murrr4er [49]

Answer:

The magnitude = 10.30 m

The direction of the vector proceeds at angle of 119.05°

Explanation:

Given that:

A vector \bar A has component A_x = -5 m and A_y = 9 m

The magnitude of vector  \bar A can be represented as:

\bar A  = \sqrt{A_x^2 + A_y^2}

\bar A  = \sqrt{(-5)^2 + (9)^2}

\bar A  = \sqrt{25 + 81}

\bar A  = \sqrt{106}

\bar A  = 10.30 m

If we make \bar A  an angle \theta with y- axis:

Then;   tan \theta  = \frac{A_x}{A_y}

tan \theta  = \frac{5}{9}

tan \theta  = 0.555

\theta  = tan⁻¹ (0.555)

\theta  = 29.05°

Angle with positive x-axis = 90 + \theta  

= 90° + 29.05°

= 119.05°

5 0
3 years ago
A constant magnetic field passes through a single rectangular loop whose dimensions are 0.35 m × 0.55 m. The magnetic field has
Pani-rosa [81]

Answer:

Part a)

EMF = 0.38 V

Part b)

\frac{dA}{dt} = 0.43 m^2/s

Explanation:

Part a)

Initial value of magnetic flux is given as

\phi_1 = BAcos\theta

\phi_1 = (2.1)(0.35 \times 0.55) cos65

so we have

\phi_1 = 0.17 Wb

Final flux through the loop is given as

\phi_2 = 0

now EMF is given as

EMF = \frac{\phi_1 - \phi_2}{\Delta t}

EMF = \frac{0.17 - 0}{0.45}

EMF = 0.38 V

Part b)

If magnetic field is constant while Area is changing

So EMF is given as

E = Bcos65 \times \frac{dA}{dt}

0.38 = 2.1 cos65(\frac{dA}{dt})

\frac{dA}{dt} = 0.43 m^2/s

5 0
3 years ago
What is the mass of an object if a force of 34 N produces an acceleration of 4 m/s^2?
Paha777 [63]
F=ma

F/a=m

34/4 =8.5

8.5 kilograms
8 0
3 years ago
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