Thing 1 and Thing 2 push with a force of 2000 N to move a rather small 500 kg elephant 30 m across the kitchen floor. How much w
1 answer:
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Answer:
a) 25.5°(south of east)
b) 119 s
c) 238 m
Explanation:
solution:
we have river speed =2 m/s
velocity of motorboat relative to water is =4.2 m/s
so speed will be:
a) =
+
solving graphically
=4.7 m/s
Ф=
=25.5°(south of east)
b) time to cross the river: t==
=119 s
c) d==(2)(119)=238 m
note :
pic is attached
Answer:
P = 7.28 N.s
Explanation:
given,
initial momentum of cue ball in x- direction,P₁ = 9 N.s
momentum of nine ball in x- direction, P₂ = 2 N.s
momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s
momentum of the cue after collision = ?
using conservation of momentum
in x- direction
P₁ + p = x + P₂
p is the initial momentum of the nine balls which is equal to zero.
9 + 0 = x + 2
x = 7 N.s
momentum in x-direction.
equating along y-direction
P'₁ + p = y + P'₂
0 + 0 = y + 2
y = -2 N.s
the momentum of the cue ball after collision is equal to resultant of the momentum .
P = 7.28 N.s
the momentum of the cue ball after collision is equal to P = 7.28 N.s
Answer:
Explanation:
The two charges are q and Q - q. Let the distance between them is r
Use the formula for coulomb's law for the force between the two charges
So, the force between the charges q and Q - q is given by
For maxima and minima, differentiate the force with respect to q.
For maxima and minima, the value of dF/dq = 0
So, we get
q = Q /2
Now
the double derivate is negative, so the force is maxima when q = Q / 2 .