When the electric current moves through a wire, it makes a magnetic field. ... The strength of an electromagnet can be increased by increasing the number of loops of wire around the iron core and by increasing the current or voltage.
Answer:
V = 49.05 [m/s]
Explanation:
We can easily find the result using kinematics equations, first, we will find the distance traveled during the 5 seconds.
where:
Yo = initial position = 0
y = final position [m]
Vo = initial velocity = 0
t = time = 5 [s]
g = gravity aceleration = 9.81 [m/s^2]
The initial speed is zero, as the body drops without imparting an initial speed. Therefore:
y = 0 + (0*5) + (0.5*9.81*5^2)
y = 122.625[m]
Now using the following equation we can find the speed it reaches during the 5 seconds.
![v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f}=\sqrt{2*9.81*122.625} \\v_{f}=49.05 [m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%20%5E%7B2%7D%3D%20v_%7Bi%7D%20%5E%7B2%7D%2B%282%2Ag%2Ay%29%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2%2A9.81%2A122.625%7D%20%5C%5Cv_%7Bf%7D%3D49.05%20%5Bm%2Fs%5D)
Answer:
they are both played by hoomans
<span>9.16 meters
First, split the velocity into horizontal and vertical components.
h = 21 cos(47°) = 21 * 0.744270977 = 15.62969052 m/s
v = 21 sin(47°) = 21 * 0.731353702 = 15.35842773 m/s
Now determine how many seconds the ball had to travel to reach 57 meters.
T = 57 m / 15.62969052 m/s = 3.647 s
height of the ball at time T is
d = vT - 0.5AT^2
where
v = initial velocity
T = Time
A = acceleration due to gravity (9.8m/s^2)
Plug in the known values
d = (15.35842773 m/s)(3.647 s) - 0.5 9.8 m/s^2 (3.647 s)^2
d = 56.01219 m - 4.9 m/s^2 (13.30061s^2)
d = 56.01219 m - 65.17298 m
d = -9.1608 m
So the ball fell a total of 9.16 meters, which means that the building was 9.16 meters tall.</span>
