Question

Calculate the centripetal force exerted on the earth by the sun. Assume that the period of revolution for the earth is 365.25 days

Answer 1

Answer:

F = 3.55 x 10²² N

Explanation:

average distance of sun from earth = 1.5 × 10⁸ km

mass of earth = 6 x 10²⁴ kg

time = 365.25 days

distance = 2 π r

distance = 2 π x 1.5 x 10¹¹ m

              = 3 π x 10¹¹ m

$v = \dfrac{d}{t}$

$v = \dfrac{3 \pi \times 10^{11}}{365.25 \times 24 \times 60 \times 60}$

   v = 2.98 x 10⁴ m/s

we know centripetal force

$F = \dfrac{mv^2}{r}$

$F = \dfrac{6 \times 10^{24}\times (2.98\times 10^4)^2}{1.5\times 10^{11}}$

F = 3.55 x 10²² N