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babymother [125]
3 years ago
6

Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How hig

h (in m) above a user must the water level be to create a gauge pressure of 4.63 ✕ 105 N/m2?
Physics
1 answer:
Salsk061 [2.6K]3 years ago
4 0

Answer:

So height will be 47.387 m

Explanation:

We have given gauge pressure P=4.63\times 10^5N/m^2

Density of water \rho =997kg/m^3

Acceleration due to gravity g=9.8m/sec^2

We know that pressure is given as P=\rho gh

4.63\times 10^5=997\times 9.8\times h

h=47.387m

So height will be 47.387 m

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zheka24 [161]

Answer:

I = 21.13 mA ≈ 21 mA

Explanation:

If

I₁ = 5 mA

L₁ = L₂ = L

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ρ₁ = 1.68*10⁻⁸ Ohm-m

ρ₂ = 1.59*10⁻⁸ Ohm-m

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If we apply the equation

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If V and L are the same

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then

(V / L)₁ = (V / L)₂  ⇒     ρ₁*I₁ / S₁ = ρ₂*I₂ / S₂

If

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we have

ρ₁*I₁ / (0.25*π*D²) = ρ₂*I₂ / (π*D²)

⇒    I₂ = 4*ρ₁*I₁ / ρ₂

⇒     I₂ = 4*1.68*10⁻⁸ Ohm-m*5 mA / 1.59*10⁻⁸ Ohm-m

⇒     I₂ = 21.13 mA

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