Question

Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How high (in m) above a user must the water level be to create a gauge pressure of 4.63 ✕ 105 N/m2?

Answer 1

Answer:

So height will be 47.387 m

Explanation:

We have given gauge pressure $P=4.63\times 10^5N/m^2$

Density of water $\rho =997kg/m^3$

Acceleration due to gravity $g=9.8m/sec^2$

We know that pressure is given as $P=\rho gh$

$4.63\times 10^5=997\times 9.8\times h$

$h=47.387m$

So height will be 47.387 m