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babymother [125]

3 years ago

6

Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How hig

h (in m) above a user must the water level be to create a gauge pressure of 4.63 ✕ 105 N/m2?

1 answer:

Salsk061 [2.6K]3 years ago

4 0

Answer:

So height will be 47.387 m

Explanation:

We have given gauge pressure $P=4.63\times 10^5N/m^2$

Density of water $\rho =997kg/m^3$

Acceleration due to gravity $g=9.8m/sec^2$

We know that pressure is given as $P=\rho gh$

$4.63\times 10^5=997\times 9.8\times h$

$h=47.387m$

So height will be 47.387 m

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A man 6 feet tall walks at a rate of 5 feet per second away from a light that is 15 feet above the ground. When he is 10 feet fr

harina [27]

Answer:

$\frac{25}{3}ft/s$

Explanation:

Height of man= 6ft

Height of light=1 5ft

Let BC=x and CD=y

BD=x+y

Triangle ABD and ECD are similar

When two triangles are similar then the ratio of their corresponding sides are equal

$\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{15}{6}=\frac{x+y}{y}$

$\frac{5}{2}=\frac{x+y}{y}$

$5y=2x+2y$

$5y-2y=2x$

$3y=2x$

Differentiate w.r.t t

$2\frac{dx}{dt}=3\frac{dy}{dt}$

We have $\frac{dx}{dt}=5ft/s$

Substitute the value then we get

$2\times 5=3\frac{dy}{dt}$

$\frac{dy}{dt}=\frac{2\times 5}{3}=10/3ft/s$

Rate at which the tip of shadow is moving= $\frac{dx}{dt}+\frac{dy}{dt}$

Rate at which the tip of shadow is moving= $5+\frac{10}{3}=\frac{15+10}{3}ft/s$

Rate at which the tip of shadow is moving= $\frac{25}{3}ft/s$

5 0

3 years ago

At 2:00 p.m. a car's speedometer reads 30 mi/h. At 2:30 p.m. it reads 50 mi/h. Show that at some time between 2:00 and 2:30 the

Gelneren [198K]

Answer:

The acceleration is exactly 40 mi/h² as shown

Explanation:

Given;

initial velocity of the car, u = 30 mi/h

final velocity of the car, v = 50 mi/h

change in velocity, ΔV = v - u

ΔV = 50 mi/h - 30 mi/h = 20 mi/h

initial time, t₁ = 2:00 PM

final time, t₂ = 2:30 PM

Change in time, Δt = t₂ - t₁

Δt = 2: 30 - 2:00 = 30 mins = 0.5 hour

Acceleration is given as change in velocity per change in time;

a = ΔV / Δt

$a = \frac{20 \ mi/h}{0.5 \ h}\\\\a = 40 \ mi/h^2 \ (shown)\\\\$

Therefore, the acceleration is exactly 40 mi/h² as shown.

6 0

3 years ago

The center of mass of a 0.3 kg (non-uniform) meter stick is located at its 46-cm mark. What is the magnitude of the torque (in N

Sati [7]

Answer:

15cm

Explanation:

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4 years ago

A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q

Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges $q_1$ and $q_2$ separated by a distance d, the magnitude of the electrostatic force F between them is:

$F = k \frac{|q_1q_2|}{d^2}$

where $k$ is Coulomb's constant.

Taking the values:

$d = 4.6 \ 10^{-15} m$

$q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}$

and knowing the value of the Coulomb's constant:

$k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}$

Taking all this in consideration:

$F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}$

$F = 120.85 \ N$

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3 years ago

Why might political parties prefer closed primaries to open primaries

sweet [91]

In a closed primary, only voters registered with a given party can vote in that party's primary.

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3 years ago