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dezoksy [38]
3 years ago
15

A short 6061-T6 aluminum cylindrical block, having an original diameter of 20mm and a length of 75mm, is placed in a compression

machine and tightened until the applied axial load is 5kN. Determine (a) the decrease in its length and (b) its new diameter.
Un bloque cilíndrico corto de aluminio 6061-T6, que tiene un diámetro original de 20 mm y una longitud de 75 mm, se coloca en una máquina de compresión y se aprieta hasta que la carga axial aplicada sea de 5 kN. Determine (a) la disminución de su longitud y (b) su nuevo diámetro.

Physics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

hi apner how is ur going for the weekend on your way home

Explanation:

hi there is that something you could help me

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Which one of the following temperatures (in °C) is equivalent to 294 K?
vaieri [72.5K]

Answer:

21

Explanation: its actually 20.85 but i guess they round to 21

5 0
3 years ago
A 2000 g of C 14 is left to decay radioactively the half-life of Corbin 14 is approximately 5700 years what fraction of that sam
ahrayia [7]

Answer:

  1/8

Explanation:

17,100 years is 3 times the half-life of 5,700 years. After each half-life, half remains, so the amount remaining after 3 half-lives is ...

  (1/2)(1/2)(1/2) = 1/8

1/8 of the sample remains after 17,100 years.

8 0
3 years ago
Read 2 more answers
Calculate the induced electric field (in V/m) in a 40-turn coil with a diameter of 11 cm that is placed in a spatially uniform m
Naddik [55]

Answer:

Explanation:

Given that,

Number of turn N = 40

Diameter of the coil d= 11cm = 0.11m

Then, radius = d/2 = 0.11/2 =0.055m

r = 0.055m

Then, the area is given as

A =πr²

A = π × 0.055²

A = 9.503 × 10^-3 m²

Magnetic Field B = 0.35T

Magnetic field reduce to zero in 0.1s, t = 0.1s

so we want to find induce electric field. To find the electric field,(E) we need to find the electric potential (V).

E.M.F is given as

ε = —N • dΦ/dt

Where magnetic flux is given as

Φ = BA

Then, ε = —N • dΦ/dt

ε = —N • dBA/dt

ε = —NBA/t

Then, its magnitude is

ε = NBA/t

Inserting the values of N, B, A and t

ε = 40×0.35×9.503×10^-3/0.1

ε = 1.33 V

Then, using the relationship between Electric field and electric potential

V = Ed

ε = E•d

E = ε/d

E = 1.33/0.11

E = 12.09 V/m

7 0
4 years ago
An attack helicopter is equipped with a 20- mm cannon that fires 88.7 g shells in the forward direction with a muzzle speed of 9
Svetradugi [14.3K]
The impulse imparted to the shells equals the change in the momentum:
Fav*(Delta t)= Delta m*v.
The mass change is
Delta m= n*m= (89.9shells)*(88.7g)=7.97Kg
So the average force is
F=((v)*(Delta m))/t= ((929)*(7.97))/4.84=1529.78 N
Since the velocity of the shells is much greater than the velocity of the helicopter, there is no need to use relative velocity.



4 0
3 years ago
Match the measurement with the prober SI unit.
padilas [110]

Answer:

Your question is incomplete

8 0
3 years ago
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