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3 years ago

What mass of water is needed to react with 32.9 g Li3N?

Chemistry

1 answer:

laiz [17]3 years ago

8 0

Answer:

The answer to your question is 50.76 g of H₂O

Explanation:

Data

mass of water = ?

mass of Li₃N = 32.9 g

Process

1.- Write the balanced chemical reaction

Li₃N + 3H₂O ⇒ 3LiOH + NH₃

2.- Calculate the molar mass of Li₃N and H₂O

Li₃N = (3 x 7) + (1 x 14) = 35 g

H₂O = (2 x 1) + (16 x 1) = 18 g

3.- Use proportions to calculate the mass of water

35 g of Li₃N ---------------- (3 x 18) g of water

32.9 g of Li₃N ------------ x

x = (32.9 x 54)/35

x = 1776.6/35

x = 50.76 g of H₂O

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3 years ago