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Alik [6]
3 years ago
15

2.22 (a) Briefly cite the main differences between ionic, covalent, and metallic bonding. (b) State the Pauli exclusion principl

e.
Chemistry
1 answer:
Alja [10]3 years ago
4 0

Answer: Ioniç bond is also called electrovalent bond. It involves the transfer of electrons from positively charged ions to negatively charged ions. covalent bond is a type of chemical bond that involves electrons sharing by atoms of a molecule in order to achieve a stable electronic configuration.. Metallic bond is a type of chemical bond that forms between metal atoms and it occurs when positive metal ions are attracted to a negatively charged electron that are not associated with a single atom. The differences can be seen in the definitions above.

Pauli exclusion principle states that electrons which are identical cannot have the same quantum state.

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It takes 53.0 J to raise the temperature of an 11.0 g piece of unknown metal from 13.0∘C to 24.2 ∘
jasenka [17]
You need to use q = mc(delta t) 
<span>Solve for c: </span>

<span>c = q / m(delta t) </span>

<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>

<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
7 0
3 years ago
Which option draws the correct conclusion from the following case study?
trasher [3.6K]

Answer:

I believe the answer The case study was influenced by bias, and led to incorrect conclusions being drawn. plz correct me if I am wrong

Explanation:

4 0
4 years ago
Read 2 more answers
Which of the following phrases describes valence electrons?
kykrilka [37]

Answer:

C

Explanation:

because valence electrons are located at the last energy level

7 0
4 years ago
A compound that is composed of only carbon and hydrogen contains 80.0% c and 20.0% h by mass. What is the empirical formula of t
gladu [14]

<u>Solution</u> : Emperical Formula =  CH_{3}

Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.

In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.

Given : 80.0g Carbon

            20.0g Hydrogen

First convert the given masses into moles.

80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}

20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}

Value of each mole divided by the smallest number of moles and then round off.

Moles ratio of the element are

\frac{6.66}{6.66}\text{mole of C}= 1

\frac{20.0}{6.66}\text{mole of C}= 3

This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.

Emperical Formula =  CH_{3}

3 0
4 years ago
A sample of nitrogen gas had a volume of 500. mL, a pressure in its closed container of 740 torr, and a temperature of 25 °C. Wh
Nat2105 [25]

Answer:

527.68 mL

Explanation:

We will assume that nitrogen is behaving as ideal gas here.

For ideal gas the gas law is:

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Where

P1= initial pressure = 740 torr

V1= initial volume = 500mL

T1= initial temperature = 25⁰C = 298 K

P2= final pressure = 760 torr

V2= final volume = ?

T2= final temperature = 50⁰C = 323 K

Putting values in the gas law

Final volume = \frac{740X500X323}{298X760}= 527.68 mL

5 0
3 years ago
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