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Alik [6]
3 years ago
15

2.22 (a) Briefly cite the main differences between ionic, covalent, and metallic bonding. (b) State the Pauli exclusion principl

e.
Chemistry
1 answer:
Alja [10]3 years ago
4 0

Answer: Ioniç bond is also called electrovalent bond. It involves the transfer of electrons from positively charged ions to negatively charged ions. covalent bond is a type of chemical bond that involves electrons sharing by atoms of a molecule in order to achieve a stable electronic configuration.. Metallic bond is a type of chemical bond that forms between metal atoms and it occurs when positive metal ions are attracted to a negatively charged electron that are not associated with a single atom. The differences can be seen in the definitions above.

Pauli exclusion principle states that electrons which are identical cannot have the same quantum state.

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In an experiment, zinc chlorate decomposed according to the following chemical equation.
mote1985 [20]

Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Explanation :

First we have to calculate the moles of Zn(ClO_3)_2

\text{ Moles of }Zn(ClO_3)_2=\frac{\text{ Mass of }Zn(ClO_3)_2}{\text{ Molar mass of }Zn(ClO_3)_2}=\frac{150g}{232.29g/mole}=\frac{150}{232.29}mole

Now we have to calculate the moles of O_2

The balanced chemical reaction is,

Zn(ClO_3)_2\rightarrow ZnCl_2+3O_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Zn(ClO_3)_2 react to give 3 mole of O_2

So, \frac{150}{232.29} moles of Zn(ClO_3)_2 react to give \frac{150}{232.29}\times \frac{3}{1} moles of O_2

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(\frac{150}{232.29}\times \frac{3}{1})mole\times (31.998g/mole)=\frac{150\times 3\times 31.998}{232.29\times 1}g

Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

6 0
3 years ago
Read 2 more answers
5.0 g of NaCl is dissolved in water, and the solution is brought to a final volume of 150 mL. What is the molarity of this solut
Ksju [112]

Answer:

Molarity is a sort of concentration for solutions. When you talk about it, means mols of solute, that are in 1000 ml of solution. The molarity at this is 0.57M

Explanation:

As you have the solution in a volume of 150ml with 5 g of solute, in 1000 ml how much solute, do u have? The answer is 33.333g so now, you have to take the molar mass of NaCl and get the mols. Mass/molar mass, you will get the moles, so 33,3333 g / 58,44 g/m is 0.570 moles. That's M

6 0
3 years ago
A colloid in which a liquid is dispersed in a solid is called a(n)
Svetach [21]

Answer:

GEL

Explanation:

8 0
2 years ago
A rock climbing group reached the top of Mount Everest in the Himalayan mountains. Mount Everest is about 29,000 feet above sea
Maslowich

Answer:

Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.

7 0
3 years ago
What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
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