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2 years ago

Do compounds with different molecular formulas have different chemical properties

1 answer:

7 0

Saying I have two different compounds with different molecular formula. One is compound NaCl, the other one is compound H2O. They will have different chemical properties such as their melting and boiling point. Therefore the answer is Yes.

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If the hydrogen ion concentration is 10-7M, what is the pH of the solution? Show all work.

Kobotan [32]

Remember pH=-log(H ions). So it would be pH=-log(10^-7).

6 0

3 years ago

Which segement of the heating curve shown above represents an increase in the potential energy, but no change in the kinetic ene

Ede4ka [16]

Answer: Option (b) is the correct answer.

Explanation:

Kinetic energy is defined as the energy obtained by the molecules of an object due to their motion.

Also, it is known that kinetic energy is directly proportional to temperature.

Mathematically, K.E = $\frac{3}{2}kT$

where, T = temperature

Whereas potential energy is defined as the energy obtained by an object due to its position.

Mathematically, P.E = mgh

where, m = mass

g = acceleration due to gravity

h = height

Therefore, in the given curve when temperature remains constant then kinetic energy of molecules will also remain.

Hence, we can conclude that the segment QR represents an increase in the potential energy, but no change in the kinetic energy.

7 0

2 years ago

What is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 ml of solution?

choli [55]

Answer:

$M=0.638M$

Explanation:

Hello!

In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:

$n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol$

Then, the liters of solution:

$V=325mL*\frac{1L}{1000mL} =0.325L$

Finally, the molarity turns out:

$M=\frac{0.207mol}{0.325L}\\\\M=0.638M$

Best regards!

5 0

2 years ago

Consider two solutions: solution x has a ph of 4; solution y has a ph of 7. from this information, we can reasonably conclude th

KIM [24]

Consider two solutions: solution X has a pH of 4; solution Y has a pH of 7. From this information, we can reasonably conclude that the concentration of hydrogen ions (H⁺) or hydronium ions (H₃O⁺) in solution X is thousand times as great as the concentration of hydrogen ions or hydronium ions in solution Y.
Solution X: c(H⁺) = 10∧-pH = 10⁻⁴ mol/L = 0,0001 mol/L.
Solution Y: c(H⁺) = 10⁻⁷ mol/L = 0,0000001 mol/L.
0,0001 mol/L / 0,0000001 mol/L = 1000.

3 0

3 years ago

What fraction of a Sr-90 sample remains unchanged after 87.3 years

jolli1 [7]

The answer is 1/8.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. $(1/2)^{n} = x$ ,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. $t_{1/2} = \frac{t}{n}$
where:
 $t_{1/2}$ - half-life
t - total time elapsed
n - a number of half-lives

The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
 $t_{1/2}$ = 28.8 years

We need:
n = ?
x = ?

We could first use the second equation, to calculate n:
If:
$t_{1/2} = \frac{t}{n}$ ,
Then:
$n = \frac{t}{ t_{1/2} }$
⇒ $n = \frac{87.3 years}{28.8 years}$
⇒ $n=3.03$
⇒ n ≈ 3

Now we can use the first equation to calculate the remained amount of the sample.
 $(1/2)^{n} = x$
⇒ $x=(1/2)^3$
⇒ $x= \frac{1}{8}$

8 0

3 years ago