Answer:
a
Explanation:
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Answer:
Explanation:
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GAMER MOMENT FROM LUIGI FOR⇔![\sqrt{x} x^{2} x^{2} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \alpha \alpha \alpha x_{123} \frac{x}{y} \pi \neq \geq \leq \\ \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx x^{2} \sqrt{x} \sqrt{x} \\](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20x%5E%7B2%7D%20x%5E%7B2%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%5Calpha%20%5Calpha%20%5Calpha%20x_%7B123%7D%20%5Cfrac%7Bx%7D%7By%7D%20%5Cpi%20%5Cneq%20%5Cgeq%20%5Cleq%20%5C%5C%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20x%5E%7B2%7D%20%5Csqrt%7Bx%7D%20%5Csqrt%7Bx%7D%20%5C%5C)
Magnesium Peroxydisulphate with formula of MgS₂O₈.
<h3><u>Explanation:</u></h3>
The question clearly stands on the concept of molarity and atomic weights.
The atomic weight of magnesium = 24.
The atomic weight of sulphur = 32.
The atomic weight of oxygen = 16.
The amount of magnesium present = 0.248 g
The amount of sulphur present = 0.665 g.
The amount of oxygen present = 1.31g.
So, moles of magnesium present = 0.01 moles.
Moles of sulphur present = 0.02 moles.
Moles of oxygen present = 0.08 moles.
So, mole ratio of the compound as magnesium : sulphur : oxygen = 1:2:8.
So the compound is Magnesium Peroxydisulphate with formula of MgS₂O₈.
Answer:
Hi... U should do like this
5 - 3.5=1.5 (N)
