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konstantin123 [22]
2 years ago
13

Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1.

" Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃
Chemistry
2 answers:
BARSIC [14]2 years ago
4 0
Balanced chemical reaction: <span>Pb(NO₃)₂ + 2NaI → PbI₂ + 2NaNO₃.
In this balanced chemical reaction there are two atoms of sodium, one atom of lead, two atoms of nitrogen, six atoms of oxygen and two atoms of iodine in both side of chemical reaction.
Lead has oxidation number +2, sodium has +1 and iodine -1.</span>
Pie2 years ago
4 0

Answer:

blank, 2, blank, 2

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What is the strcture for fructose C6H12O6?
djverab [1.8K]
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5 0
3 years ago
Charles's law describes the relationship of the volume and temperature of
True [87]

Answer:

The temperature would be reduced by half

Explanation:

Charles' Law => V ∝ T =>  V = kT => k = V/T

For two sets of T vs V conditions, the system constant (k) remains unchanged and k₁ = k₂ => V₁/T₁ = V₂/T₂.

Therefore, if V₁ is reduced to 1/2V₁ = V₂ => V₁/T₁ = 1/2V₁/T₂ => V₁/T₁ = V₁/2T₂

and solving for T₂ =>  1/T₁ = 1/2T₂ => 2T₂ = T₁ => T₂ = 1/2T₁

∴ The initial temperature (T₁) would be reduced by half or, T₂ = 1/2T₁

7 0
2 years ago
Consider two gases, A and B, are in a container at room temperature. What effect will the following changes have on the rate of
Oksanka [162]

Answer:

B: increase.

Explanation:

When we are considering two gases A and B in a container at room temperature .

We have to find the change on  rate of reaction when the number of molecules of gases A is doubled

Let [A]=a and [B]=b

A+B\rightarrow product

Rate of reaction

R_1=k[A][B]=kab

We know that concentration is increases with increase in number of moles

When the number of molecules of gases A is doubled then concentration of gases A increases.

Therefore ,[A]=2a

Rate of reaction

R_2=k(2a)(b)=2kab

R_2=2R_1

Hence, the rate of reaction is  2 times the initial rate of reaction.Therefore, the rate of reaction will increase when the number of molecules of gases A is doubled.

Answer: B: increase.

4 0
3 years ago
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper
Anit [1.1K]

Explanation:

Reaction equation for the given chemical reaction is as follows.

      2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}

Equation for reaction quotient is as follows.

         Q = \frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}

             = \frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}

             = 0.256

As, Q > K (= 0.12)

The effect on the partial pressure of SO_{3} as equilibrium is achieved by using Q, is as follows.

  • This means that there are too much products.
  • Equilibrium will shift to the left towards reactants.
  • More SO_{3} is formed.
  • Partial pressure of SO_{3} increases.
4 0
3 years ago
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