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Nata [24]
3 years ago
15

While performing the assays for the LDH kinetics experiment, you will pipet 25ul of 250 ug/ml LDH into 975 ul of assay buffer (T

ris, Lactate, and NAD). What is the final concentration of LDH in the assay?
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

6.25 μg/mL

Explanation:

When a dilution is made, the mass of the solute is conserved (Lavoiser's law), so the mass pipetted will be the mass in the assay. The mass is the concentration (C) multiplied by the volume (V). If the pipet solution is called 1, and the assay 2:

m1 = m2

C1*V1 = C2*V2

C1 = 250 μg/mL

V1 = 25 μL

V2 = 975 μL + 25 μL = 1000 μL (is the final volume of the assay after the addition of LDH)

250*25 = C2*1000

C2 = 6.25 μg/mL

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When 8.0 moles of methanol are reacted with 9.0 moles of oxygen, how many moles of water vapor does the reaction produce?
nadya68 [22]

Answer:

12 moles of H₂O are formed in this combustion.

Explanation:

First of all, think the reaction:

2CH₃OH (l) +  3O₂ (g) →  2CO₂ (g) + 4H₂O (g)

Ratio in the reactants is 2:3, so 2 mol of methanol need 3 mol of oxygen to react. Then 8 mol of CH₃OH, will need (8.3)/2 = 12 moles of O₂

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3 0
3 years ago
Hydroxylamine is a weak molecular base with kb = 6.6 x 10-9. what is the ph of a 0.0500 m solution of hydroxylamine?
7nadin3 [17]
Answer is: pH of hydroxylamine solution is 9,23.

Kb(NH₂OH) = 1,8·10⁻⁵<span>.
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c(NH</span>₂⁺) = c(OH⁻) = x.

c(NH₂OH<span>) = 0,05 mol/L - x.
Kb = c(NH</span>₂⁺) · c(OH⁻) / c(NH₂OH).

0,0000000066 = x² /  (0,05 mol/L - x). 

solve quadratic equation: x = c(OH⁻) = 0,000018 mol/L.<span>
pOH = -log(</span>0,000018 mol/L) = 4,74.<span>
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4 0
3 years ago
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andrew-mc [135]
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4 0
2 years ago
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IRINA_888 [86]
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2 years ago
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