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Nataly [62]
4 years ago
10

Technician A says that tie rod ends are used to connect the steering linkage to the steering knuckles. Technician B says that so

me ball and socket joints are sealed and do not require lubrication. Which technician is correct
Physics
1 answer:
Iteru [2.4K]4 years ago
8 0

Answer:

Both technicians A and B are correct.                

Explanation:

The tie rod is present as a part  of a steering system. It consists of inner end as well as  outer end. It helps in transferring force from the steering link to the steering knuckle. And this causes to turn the wheel of the vehicle.

Usually a ball joint comes with pre-greased. The sealed ball and socket joint are lubed for their life, so they does not require lubrication.

Thus both the technicians are correct.

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Briefly explain how a resonance tube works​
Lera25 [3.4K]

Answer:

As the tines of the tuning fork vibrate at their own natural frequency, they created sound waves that impinge upon the opening of the resonance tube. These impinging sound waves produced by the tuning fork force air inside of the resonance tube to vibrate at the same frequency.

4 0
2 years ago
Read 2 more answers
A transformer has an output coil with 6 times as many turns as the input coil. If the input frequency is f then the output frequ
sveticcg [70]

Answer:

d. f

Explanation:

Based on the principle of operation of transformer, when a.c voltage is applied at the terminal of the primary coil (input coil), an alternating magnetic flux is produced in the iron core which links the secondary coil (output coil).

Also, an alternating e.m.f of <em>the same frequency</em> as that of primary coil (input coil) <u>will be induced in the secondary coil (output coil) by mutual inductance.</u>

Thus, If the input frequency is "f" then the output frequency will be "f" (since the frequency will be the same).

The correct option is "D"

5 0
3 years ago
A vessel (see the figure) comprises of into two chambers
r-ruslan [8.4K]

Answer:

(C) 2P

Explanation:

Ideal gas law states:

PV = nRT

n (the number of moles) and R (ideal gas constant) are constant, so we can say:

(PV / T) before = (PV / T) after

Chamber X starts at pressure P, volume V, and temperature T.  At equilibrium, the pressure is Px, the volume is Vx, and temperature 3T.

PV / T = Px Vx / 3T

Chamber Y starts at pressure P, volume V, and temperature T.  At equilibrium, the pressure is Py, the volume is Vy, and temperature T.

PV / T = Py Vy / T

Substituting and simplifying:

Px Vx / 3T = Py Vy / T

Px Vx / 3 = Py Vy

Since the chambers are at equilibrium, Px = Py:

Vx / 3 = Vy

Vx = 3 Vy

The total volume is the same as before, so:

Vx + Vy = 2V

Substituting:

(3 Vy) + Vy = 2V

4 Vy = 2V

Vy = V / 2

Now if we substitute into our equation for chamber Y:

PV / T = Py (V/2) / T

PV = Py (V/2)

Py = 2P

The pressure in chamber Y (and chamber X) doubles at equilibrium.

4 0
3 years ago
Calculate the potential energy of a 1200 kg boulder on a cliff 45 m above the ground. ​
Softa [21]

Explanation:

Given mass of the object is 1200kg and it's placed at a height of 45m above the ground. As we know that potential energy is ,

\longrightarrow PE = mgh

where,

  • m is the mass of the body .
  • g is acceleration due to gravity.
  • h is the height above the ground .

Substituting the respective values ,

\longrightarrow P.E. = 1200kg * 10m/s^2* 45m

Multiply ,

\longrightarrow P.E. = 540000J

<u>Hence</u><u> the</u><u> </u><u>potential</u><u> energy</u><u> is</u><u> </u><u>5</u><u>4</u><u>0</u><u>0</u><u>0</u><u>0</u><u>J</u><u> </u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>

4 0
2 years ago
The superheroine Xanaxa, who has a mass of 65.1 kg , is pursuing the 78.7 kg archvillain Lexlax. She leaps from the ground to th
klasskru [66]

Answer:

There is net loss of gravitational energy .

Explanation:

When Xanaxa is on the ground , her potential energy is assumed to be zero . When she leaps to a height of 153 m , she gains gravitational energy . When she dives and reaches the surface , she loses potential energy and on reaching the ground her potential energy becomes zero . When she further goes down inside ground to a depth of 17.5 m , she loses potential energy further . Her potential energy becomes less than zero or negative .

Ultimately her potential energy changes from zero to negative in the whole process . So there is net loss of potential energy .

8 0
3 years ago
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