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alina1380 [7]
4 years ago
8

Two vectors A and B are added to give a resultant R. The components of A are Ax = -8.0 units and Ay = 6.0 units and the componen

ts of B are Bx= 1.0 units and By=- 1.0 units. What is the magnitude of vector R?
Physics
1 answer:
Georgia [21]4 years ago
5 0

Answer:

<em>10.09 units</em>

Explanation:

For the A

Ax = -8.0 units

Ay = 6.0 units

The resultant vector = Ra = \sqrt{A^2_{x} + A^2_{y}  }

Ra = \sqrt{(-8)^2 + 6^2  } =  10 units

For B

Bx = 1.0 units

By = -1.0 units

The resultant vector = Rb = \sqrt{B^2_{x} + B^2_{y}  }

Rb = \sqrt{1^2 + (-1)^2  } = \sqrt{2} units

Adding these two vectors A and B together, magnitude of vector R is

R = \sqrt{R^2_{a} + R^2_{b}  }

R =  \sqrt{10^2 + (\sqrt{2} ) ^2} = <em>10.09 units</em>

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