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3 years ago

A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)

Physics

1 answer:

Illusion [34]3 years ago

3 0

The work done against gravity is 100 J

Explanation:

The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:

$W=mg\Delta h$

where

m is the mass of the object

g is the acceleration of gravity

$\Delta h$ is the change in height of the object

For the object in this problem, we have:

m = 5 kg

$g=10 m/s^2$

$\Delta h = 2 m$

Substituting into the equation,

$W=(5)(10)(2)=100 J$

Learn more about work:

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3 years ago

Find the acceleration if a 32.5 N force is<br> used on an object that has a mass of<br> 128.6 kg.

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Answer:

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2 years ago

As a system expands, it absorbs 52.5 J of energy in the form of heat from the surroundings. The piston is working against a pres

Kaylis [27]

Answer:

Vi = 0.055 m³ = 55 L

Explanation:

From first Law of Thermodynamics, we know that:

ΔQ = ΔU + W

where,

ΔQ = Heat absorbed by the system = 52.5 J

ΔU = Change in Internal Energy = -102.5 J (negative sign shows decrease in internal energy of the system)

W = Work Done in Expansion by the system = ?

Therefore,

52.5 J = - 102.5 J + W

W = 52.5 J + 102.5 J

W = 155 J

Now, the work done in a constant pressure condition is given by:

W = PΔV

W = P(Vf - Vi)

where,

P = Constant Pressure = (0.5 atm)(101325 Pa/1 atm) = 50662.5 Pa

Vf = Final Volume of System = (58 L)(0.001 m³/1 L) = 0.058 m³

Vi = Initial Volume of System = ?

Therefore,

155 J = (50662.5 Pa)(0.058 m³ - Vi)

Vi = 0.058 m³ - 155 J/50662.5 Pa

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3 years ago

What is the velocity of a car that travels -50 meters in 5 seconds then 10 meters in 5 seconds

diamong [38]

Answer:

2 m/s

Explanation:

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v = d/t

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v = 2 m/s

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3 years ago

A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)​

A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)