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joja [24]
3 years ago
10

A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)​

Physics
1 answer:
Illusion [34]3 years ago
3 0

The work done against gravity is 100 J

Explanation:

The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:

W=mg\Delta h

where

m is the mass of the object

g is the acceleration of gravity

\Delta h is the change in height of the object

For the object in this problem, we have:

m = 5 kg

g=10 m/s^2

\Delta h = 2 m

Substituting into the equation,

W=(5)(10)(2)=100 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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A water balloon is thrown horizontally from a tower that is 45 m high. It strikes the shoes of an unsuspecting passerby who is 4
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14.85 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) of tower = 45 m

Horizontal distance (s) moved by the balloon = 45 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the balloon to hit the shoe of the passerby. This is illustrated below:

Height (h) of tower = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

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45 = ½ × 9.8 × t²

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Divide both side by 4.9

t² = 45/4.9

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t = √(45/4.9)

t = 3.03 s

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Time (t) = 3.03 s

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Divide both side by 3.03

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Thus, the magnitude of the horizontal velocity of the balloon was 14.85 m/s

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