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3 years ago

Which model of acids and bases would NOT define NH3 as a base (even though it is considered one by the other models)?

Chemistry

1 answer:

prohojiy [21]3 years ago

4 0

Answer:

<em>The correct option is A) Arrhenius</em>

Explanation:

According to the Arrhenius concept of acids and bases, an acid must produce H+ ions when it is present in a solution and the base must produce OH- ions when placed in a solution.

Ammonia does not contain OH- ions of its own when dissolved in water.

The reaction of ammonia dissolving is water can be written as:

NH3 + H2O ⇌ NH4+ + OH−

As we can see from the equation, ammonia does form OH- ions but it does not have OH- ions on its own.

Hence, according to the Arrhenius concept, NH3 is not a base.

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Why does a solid have a definite shape and volume?

stellarik [79]

Answer:

Explanation:

Particles in a solid have fixed locations in a volume that does not change. Solids have a definite volume and shape because particles in a solid vibrate around fixed locations.

6 0

3 years ago

Zinc has a density of 7.10 g/cm3. If a cylinder of zinc weighing 46.77 g is completely immersed in a graduated cylinder that ori

scoundrel [369]

Zinc density = 7.10 = 46.77/x ==> x = 46.77/7.10 =6.6 cm3 or 6.6 ml
New water level = 33.33+ 6.6 = 39.93 ml
Can you mark it brainliest if my answer is correct?

4 0

3 years ago

The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio

iren2701 [21]

Answer : The correct option is, (B) $CO_2$

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

$R\propto \sqrt{\frac{1}{M}}$

or,

$(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}$ ..........(1)

where,

$R_1$ = rate of effusion of unknown gas = $11.9\text{ mL }min^{-1}$

$R_2$ = rate of effusion of oxygen gas = $14.0\text{ mL }min^{-1}$

$M_1$ = molar mass of unknown gas = ?

$M_2$ = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the above formula 1, we get:

$(\frac{11.9\text{ mL }min^{-1}}{14.0\text{ mL }min^{-1}})=\sqrt{\frac{32g/mole}{M_1}}$

$M_1=44.2g/mole$

The unknown gas could be carbon dioxide $(CO_2)$ that has approximately 44 g/mole of molar mass.

Thus, the unknown gas could be carbon dioxide $(CO_2)$

5 0

3 years ago

You’ll soon make two pieces of ice with the approximate shapes shown in the image. Both pieces of ice have the same mass and vol

Montano1993 [528]

Is there an image? I'll stay to help you.

3 0

3 years ago

What is the ratio of the diffusion rates of cl2 and o2? rate cl2 : o2 = 0.47 0.67 0.45 0.69 1.5?

matrenka [14]

The ratio of the diffusion rate of Cl2 and O2 is 1.5

calculation
rate of diffusion Cl2/ rate of diffusion O2 =√ molar mass of Cl2/ molar mass of O2

molar mass of Cl2 = 35.5 x2 = 71 g/mol
molar mass O2 = 16 x2 =32g/mol

that is rate of diffusion Cl2/ rate of diffusion of O2 =√ 71/ 32= 1.5

7 0

3 years ago