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Dmitry [639]
3 years ago
12

What resource is nonrewable? A. Pigs B. Wheat C. Water D. Petroleum

Chemistry
2 answers:
Dovator [93]3 years ago
6 0
Answer to the question

D. Petroleum
hram777 [196]3 years ago
6 0

Answer:

d

Explanation:

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Cobalt chloride Select one: a. Does not exist as a hydrate b. Forms a single hydrate which may be pink or blue c. Forms differen
Anarel [89]

Answer:

c. Forms different hydrates which have different colors

Explanation:

4 0
3 years ago
If you add 25.0 mL of water to 125 mL of a 0.150 M LiOH solution, what will be the molarity of the resulting diluted solution?
Alborosie

Concentration is the number of moles of solute in a fixed volume of solution

Concentration(c) = number of moles of solute(n) / volume of solution (v)

25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.

original solution molarity - 0.150 M

number of moles of LiOH in 1 L - 0.150 mol

number of LiOH moles in 0.125 L  - 0.150 mol/ L x 0.125 L = 0.01875 mol

when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases

new volume -  125 mL + 25 mL = 150 mL

therefore new molarity is

c = 0.01875 mol / 0.150 L  = 0.125 M

answer is 0.125 M

7 0
3 years ago
What is the chemical formula for Salt and hydrogen gas?
marshall27 [118]
Salt: NaCl
Hydrogen gas: H2
3 0
2 years ago
Because it lives for many years a maple tree is a
lara31 [8.8K]

Answer:

perennial

Explanation:

4 0
3 years ago
Read 2 more answers
Determine the percent ionization of a 0.225 M solution of benzoic acid. Express your answer using two significant figures.
Assoli18 [71]

Answer:

1.68% is ionized

Explanation:

The Ka of benzoic acid, C₇H₆O₂, is 6.46x10⁻⁵, the equilibrium in water of this acid is:

C₇H₆O₂(aq) + H₂O(l) ⇄ C₇H₅O₂⁻(aq) + H₃O⁺(aq)

Ka = 6.46x10⁻⁵ = [C₇H₅O₂⁻] [H₃O⁺] / [C₇H₆O₂]

<em>Where [] are concentrations in equilibrium</em>

In equilibrium, some 0.225M of the acid will react producing both C₇H₅O₂⁻ and H₃O⁺, the equilibrium concentrations are:

[C₇H₆O₂] = 0.225-X

[C₇H₅O₂⁻] = X

[H₃O⁺] = X

Replacing:

6.46x10⁻⁵ = [X] [X] / [0.225-X]

1.4535x10⁻⁵ - 6.46x10⁻⁵X = X²

1.4535x10⁻⁵ - 6.46x10⁻⁵X - X² = 0

Solving for X:

X = -0.0038. False solution, there is no negative concentrations.

X = 0.00378M. Right solution.

That means percent ionization (100 times Amount of benzoic acid ionized  over the initial concentration of the acid) is:

0.00378M / 0.225M * 100 =

<h3>1.68% is ionized</h3>
8 0
3 years ago
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