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Anit [1.1K]
3 years ago
9

For the reaction of gaseous nitrogen with gaseous hydrogen to produce gaseous ammonia, the correct equilibrium constant expressi

on is _____
Chemistry
1 answer:
exis [7]3 years ago
7 0

The solution would be like this for this specific problem:

 

First, we need to write out the balanced reaction equation for the problem:<span>

"gaseous nitrogen with gaseous hydrogen to produce gaseous ammonia" 

gaseous nitrogen + gaseous hydrogen = gaseous ammonia 

gaseous nitrogen = N2(g) 
gaseous hydrogen = H2(g) 
gaseous ammonia = NH3(g) 

In here, I’m going to show you how to balance this from start to finish: 

N2(g) + H2(g) ↔ NH3(g) (basic, unbalanced equation that shows reactants and product) 
N2(g) + H2(g) ↔ 2NH3(g) (balances the nitrogens) 
N2(g) + 3H2(g) ↔ 2NH3(g) (balances the hydrogens) => Balanced Equation 

<span>Next, we write the Keq expression of the balanced reaction:

Keq = (∏[products]^n) /(∏[reactants]^n) 
Keq = [NH3]^2 / [[N2][H2]]^3 


Therefore, the correct equilibrium constant expression is Keq = (NH3)2 / (N2)(H2)3.</span></span>

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i. The given alkene X, that is subject to ozonolysis would be 2-methyl-2-pentene. Upon exposure to ozone, an ozonide is initially formed, after which it is broken down into 2 products - acetone and propanal, both with the molecular formula C₃H₆O.

The given compound X is 2-methyl pent-2-ene. When it is reacted with ozone it forms an ozonide in the first step. In the second step the reduce to forms acetone and propanal.

ii. The formulas of Y is CH_3-CO-CH_3 and Z is CH_3-CH_2-CHO. They are functional isomers as they have the same molecular formula but different functional groups - ketone and aldehyde.

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Learn more about the ozonolysis here:

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