If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
Area is length times width so it is 3 times 3 since a square sides are all the same
Y=2x+6
(This is me filling space)
There are infinite equivalent fraction can be obtained just multiple by any number to both numerator and denominator and you will find equivalent fraction !
as 42/16, 63/24 etc
Answer:
so the lowest term is 1/10
hope this helps u
